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P = poisscdf(X,lambda)
P = poisscdf(X,lambda) computes the Poisson cdf at each of the values in X using the corresponding parameters in lambda. X and lambda can be vectors, matrices, or multidimensional arrays that have the same size. A scalar input is expanded to a constant array with the same dimensions as the other input. The parameters in lambda must be positive.
The Poisson cdf is
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For example, consider a Quality Assurance department that performs random tests of individual hard disks. Their policy is to shut down the manufacturing process if an inspector finds more than four bad sectors on a disk. What is the probability of shutting down the process if the mean number of bad sectors (λ) is two?
probability = 1-poisscdf(4,2) probability = 0.0527
About 5% of the time, a normally functioning manufacturing process produces more than four flaws on a hard disk.
Suppose the average number of flaws (λ) increases to four. What is the probability of finding fewer than five flaws on a hard drive?
probability = poisscdf(4,4) probability = 0.6288
This means that this faulty manufacturing process continues to operate after this first inspection almost 63% of the time.
cdf, poisspdf, poissinv, poisstat, poissfit, poissrnd
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