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g = finverse(f)
g = finverse(f,v)
g = finverse(f) returns the functional inverse of f. f is a scalar sym representing a function of one symbolic variable, say x. Then g is a scalar sym that satisfies g(f(x)) = x. That is, finverse(f) returns f–1, provided f–1 exists.
g = finverse(f,v) uses the symbolic variable v, where v is a sym, as the independent variable. Then g is a scalar sym that satisfies g(f(v)) = v. Use this form when f contains more than one symbolic variable.
Compute functional inverse for the trigonometric function:
syms x u v; finverse(1/tan(x))
The result is:
ans = atan(1/x)
Compute functional inverse for the exponent function:
finverse(exp(u - 2*v), u)
The result is:
ans = 2*v + log(u)
![]() | findsym (sym) | fix (sym) | ![]() |

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