Calculate cross product of two 3-by-1 vectors

Utilities/Math Operations

The
3x3 Cross Product block computes cross (or vector) product of two
vectors, *A* and *B*, by generating
a third vector, *C*, in a direction normal to the
plane containing *A* and *B*, and
with magnitude equal to the product of the lengths of *A* and *B* multiplied
by the sine of the angle between them. The direction of *C* is
that in which a right-handed screw would move in turning from *A* to *B*.

$$\begin{array}{c}A={a}_{1}i+{a}_{2}j+{a}_{3}k\\ B={b}_{1}i+{b}_{2}j+{b}_{3}k\\ C=A\times B=\left|\begin{array}{ccc}i& j& k\\ {a}_{1}& {a}_{2}& {a}_{3}\\ {b}_{1}& {b}_{2}& {b}_{3}\end{array}\right|\\ =({a}_{2}{b}_{3}-{a}_{3}{b}_{2})i+({a}_{3}{b}_{1}-{a}_{1}{b}_{3})j+({a}_{1}{b}_{2}-{a}_{2}{b}_{1})k\end{array}$$

Input | Dimension Type | Description |
---|---|---|

First | 3-by-1 vector | |

Second | 3-by-1 vector |

Output | Dimension Type | Description |
---|---|---|

First | 3-by-1 vector |

Was this topic helpful?