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Set intersection of two arrays

`C = intersect(A,B)`

```
C
= intersect(A,B,setOrder)
```

`C = intersect(A,B,___,'rows')`

`C = intersect(A,B,'rows',___)`

```
[C,ia,ib]
= intersect(___)
```

```
[C,ia,ib]
= intersect(A,B,'legacy')
```

```
[C,ia,ib]
= intersect(A,B,'rows','legacy')
```

returns the data common to both `C`

= intersect(`A,B`

)`A`

and `B`

,
with no repetitions. `C`

is in sorted order.

If

`A`

and`B`

are tables or timetables, then`intersect`

returns the set of rows common to both tables. For timetables,`intersect`

takes row times into account to determine equality, and sorts the output timetable`C`

by row times.

and
`C`

= intersect(`A,B`

,___,'rows')

treat each row of `C`

= intersect(`A,B`

,'rows',___)`A`

and each row of `B`

as
single entities and return the rows common to both `A`

and
`B`

, with no repetitions. You must specify
`A`

and `B`

and optionally can specify
`setOrder`

.

The `'rows'`

option does not support cell arrays, unless one
of the inputs is either a categorical array or a datetime array.

To find the intersection with respect to a subset of variables from a table or timetable, you can use column subscripting. For example, you can use

`intersect(A(:,`

, where),B(:,`vars`

))`vars`

is a positive integer, a vector of positive integers, a variable name, a cell array of variable names, or a logical vector. Alternatively, you can use`vars`

`vartype`

to create a subscript that selects variables of a specified type.

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