Documentation |
View transformation matrices
viewmtx
T = viewmtx(az,el)
T = viewmtx(az,el,phi)
T = viewmtx(az,el,phi,xc)
viewmtx computes a 4-by-4 orthographic or perspective transformation matrix that projects four-dimensional homogeneous vectors onto a two-dimensional view surface (e.g., your computer screen).
T = viewmtx(az,el) returns an orthographic transformation matrix corresponding to azimuth az and elevation el. az is the azimuth (i.e., horizontal rotation) of the viewpoint in degrees. el is the elevation of the viewpoint in degrees. This returns the same matrix as the commands
view(az,el) T = view
but does not change the current view.
T = viewmtx(az,el,phi) returns a perspective transformation matrix. phi is the perspective viewing angle in degrees. phi is the subtended view angle of the normalized plot cube (in degrees) and controls the amount of perspective distortion.
Phi | Description |
---|---|
0 degrees | Orthographic projection |
10 degrees | Similar to telephoto lens |
25 degrees | Similar to normal lens |
60 degrees | Similar to wide-angle lens |
T = viewmtx(az,el,phi,xc) returns the perspective transformation matrix using xc as the target point within the normalized plot cube (i.e., the camera is looking at the point xc). xc is the target point that is the center of the view. You specify the point as a three-element vector, xc = [xc,yc,zc], in the interval [0,1]. The default value is xc = [0,0,0].
A four-dimensional homogenous vector is formed by appending a 1 to the corresponding three-dimensional vector. For example, [x,y,z,1] is the four-dimensional vector corresponding to the three-dimensional point [x,y,z].
Determine the projected two-dimensional vector corresponding to the three-dimensional point (0.5,0.0,-3.0) using the default view direction. Note that the point is a column vector.
A = viewmtx(-37.5,30); x4d = [.5 0 -3 1]'; x2d = A*x4d; x2d = x2d(1:2) x2d = 0.3967 -2.4459
These vectors trace the edges of a unit cube:
x = [0 1 1 0 0 0 1 1 0 0 1 1 1 1 0 0]; y = [0 0 1 1 0 0 0 1 1 0 0 0 1 1 1 1]; z = [0 0 0 0 0 1 1 1 1 1 1 0 0 1 1 0];
Transform the points in these vectors to the screen, then plot the object.
A = viewmtx(-37.5,30); [m,n] = size(x); x4d = [x(:),y(:),z(:),ones(m*n,1)]'; x2d = A*x4d; x2 = zeros(m,n); y2 = zeros(m,n); x2(:) = x2d(1,:); y2(:) = x2d(2,:); figure plot(x2,y2)
Use a perspective transformation with a 25 degree viewing angle:
A = viewmtx(-37.5,30,25); x4d = [.5 0 -3 1]'; x2d = A*x4d; x2d = x2d(1:2)/x2d(4) x2d = 0.1777 -1.8858
Transform the cube vectors to the screen and plot the object:
A = viewmtx(-37.5,30,25); [m,n] = size(x); x4d = [x(:),y(:),z(:),ones(m*n,1)]'; x2d = A*x4d; x2 = zeros(m,n); y2 = zeros(m,n); x2(:) = x2d(1,:)./x2d(4,:); y2(:) = x2d(2,:)./x2d(4,:); figure plot(x2,y2)