Consider the problem of finding a solution to a system of nonlinear equations whose Jacobian is sparse. The dimension of the problem in this example is 1000. The goal is to find x such that F(x) = 0. Assuming n = 1000, the nonlinear equations are
function [F,J] = nlsf1(x) % Evaluate the vector function n = length(x); F = zeros(n,1); i = 2:(n-1); F(i) = (3-2*x(i)).*x(i)-x(i-1)-2*x(i+1) + 1; F(n) = (3-2*x(n)).*x(n)-x(n-1) + 1; F(1) = (3-2*x(1)).*x(1)-2*x(2) + 1; % Evaluate the Jacobian if nargout > 1 if nargout > 1 d = -4*x + 3*ones(n,1); D = sparse(1:n,1:n,d,n,n); c = -2*ones(n-1,1); C = sparse(1:n-1,2:n,c,n,n); e = -ones(n-1,1); E = sparse(2:n,1:n-1,e,n,n); J = C + D + E; end
xstart = -ones(1000,1); fun = @nlsf1; options = optimoptions(@fsolve,'Display','iter',... 'Algorithm','trust-region-reflective',... 'Jacobian','on','PrecondBandWidth',0); [x,fval,exitflag,output] = fsolve(fun,xstart,options);
A starting point is given as well as the function name. The
default method for
fsolve is trust-region-dogleg,
so it is necessary to specify
options argument in order to select the trust-region-reflective
algorithm. Setting the
Display option to
display the output at each iteration. Setting
fsolve to use the Jacobian information available
The commands display this output:
Norm of First-order Iteration Func-count f(x) step optimality 0 1 1011 19 1 2 16.1942 7.91898 2.35 2 3 0.0228027 1.33142 0.291 3 4 0.000103359 0.0433329 0.0201 4 5 7.3792e-07 0.0022606 0.000946 5 6 4.02299e-10 0.000268381 4.12e-05 Equation solved, inaccuracy possible. The vector of function values is near zero, as measured by the default value of the function tolerance. However, the last step was ineffective.
A linear system is (approximately) solved in each major iteration
using the preconditioned conjugate gradient method. Setting
options means a diagonal preconditioner is used. (
the bandwidth of the preconditioning matrix. A bandwidth of 0 means
there is only one diagonal in the matrix.)
From the first-order optimality values, fast linear convergence occurs. The number of conjugate gradient (CG) iterations required per major iteration is low, at most five for a problem of 1000 dimensions, implying that the linear systems are not very difficult to solve in this case (though more work is required as convergence progresses).
If you want to use a tridiagonal preconditioner, i.e., a preconditioning
matrix with three diagonals (or bandwidth of one), set
options = optimoptions(@fsolve,'Display','iter','Jacobian','on',... 'Algorithm','trust-region-reflective','PrecondBandWidth',1); [x,fval,exitflag,output] = fsolve(fun,xstart,options);
In this case the output is
Norm of First-order Iteration Func-count f(x) step optimality 0 1 1011 19 1 2 16.0839 7.92496 1.92 2 3 0.0458181 1.3279 0.579 3 4 0.000101184 0.0631898 0.0203 4 5 3.16615e-07 0.00273698 0.00079 5 6 9.72481e-10 0.00018111 5.82e-05 Equation solved, inaccuracy possible. The vector of function values is near zero, as measured by the default value of the function tolerance. However, the last step was ineffective.
Note that although the same number of iterations takes place, the number of PCG iterations has dropped, so less work is being done per iteration. See Preconditioned Conjugate Gradient Method.
is the default) means that the solver uses Cholesky factorization
rather than PCG.