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`fsolve`

solves systems of nonlinear equations.
However, it does not allow you to include any constraints, even bound
constraints. The question is, how can you solve systems of nonlinear
equations when you have constraints?

The short answer is, there are no guarantees that a solution exists that satisfies your constraints. There is no guarantee that any solution exists, even one that does not satisfy your constraints. Nevertheless, there are techniques that can help you search for solutions that satisfy your constraints.

To illustrate the techniques, consider how to solve the equations

$$\begin{array}{c}{F}_{1}(x)=\left({x}_{1}+1\right)\left(10-{x}_{1}\right)\frac{1+{x}_{2}^{2}}{1+{x}_{2}^{2}+{x}_{2}}\\ {F}_{2}(x)=\left({x}_{2}+2\right)\left(20-{x}_{2}\right)\frac{1+{x}_{1}^{2}}{1+{x}_{1}^{2}+{x}_{1}},\end{array}$$ | (11-9) |

where the components of * x* must be nonnegative.
Clearly, there are four solutions to the equations:

* x* = (–1,–2)

There is only one solution that satisfies the constraints, namely *x* = (10,20).

To solve the equations numerically, first enter code to calculate * F*(

```
function F = fbnd(x)
F(1) = (x(1)+1)*(10-x(1))*(1+x(2)^2)/(1+x(2)^2+x(2));
F(2) = (x(2)+2)*(20-x(2))*(1+x(1)^2)/(1+x(1)^2+x(1));
```

Save this code as the file `fbnd.m`

on your MATLAB^{®} path.

Generally, a system of * N* equations in

`x0`

,
and run `fsolve`

starting at each `x0`

.For this example, to look for a solution to Equation 11-9, take 10 random points that are normally distributed with mean 0 and standard deviation 100.

rng default % for reproducibility N = 10; % try 10 random start points pts = 100*randn(N,2); % initial points are rows in pts soln = zeros(N,2); % allocate solution opts = optimoptions('fsolve','Display','off'); for k = 1:N soln(k,:) = fsolve(@fbnd,pts(k,:),opts); % find solutions end

Examine the solutions in `soln`

, and you find
several that satisfy the constraints.

There are three `fsolve`

algorithms. Each
can lead to different solutions.

For this example, take `x0 = [1,9]`

and
examine the solution each algorithm returns.

x0 = [1,9]; opts = optimoptions(@fsolve,'Display','off',... 'Algorithm','trust-region-dogleg'); x1 = fsolve(@fbnd,x0,opts)

x1 = -1.0000 -2.0000

```
opts.Algorithm = 'trust-region';
x2 = fsolve(@fbnd,x0,opts)
```

x2 = -1.0000 20.0000

```
opts.Algorithm = 'levenberg-marquardt';
x3 = fsolve(@fbnd,x0,opts)
```

x3 = 0.9523 8.9941

Here, all three algorithms find different solutions for the
same initial point. In fact, `x3`

is not even a solution,
but is simply a locally stationary point.

`lsqnonlin`

tries to minimize the sum of
squares of the components of a vector function * F*(

`lsqnonlin`

accepts
bound constraints.Formulate the example problem for `lsqnonlin`

and
solve it.

```
lb = [0,0];
rng default
x0 = 100*randn(2,1);
[x,res] = lsqnonlin(@fbnd,x0,lb)
```

x = 10.0000 20.0000 res = 2.4783e-25

You can use `lsqnonlin`

with the Global Optimization Toolbox `MultiStart`

solver
to search over many initial points automatically. See MultiStart Using lsqcurvefit or lsqnonlin (Global Optimization Toolbox).

You can reformulate the problem and use `fmincon`

as
follows:

Give a constant objective function, such as

`@(x)0`

, which evaluates to`0`

for each`x`

.Set the

`fsolve`

objective function as the nonlinear equality constraints in`fmincon`

.Give any other constraints in the usual

`fmincon`

syntax.

For this example, write a function file for the nonlinear inequality constraint.

function [c,ceq] = fminconstr(x) c = []; % no nonlinear inequality ceq = fbnd(x); % the fsolve objective is fmincon constraints

Save this code as the file `fminconstr.m`

on
your MATLAB path.

Solve the constrained problem.

lb = [0,0]; % lower bound constraint rng default % reproducible initial point x0 = 100*randn(2,1); opts = optimoptions(@fmincon,'Algorithm','interior-point','Display','off'); x = fmincon(@(x)0,x0,[],[],[],[],lb,[],@fminconstr,opts)

x = 10.0000 20.0000

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