freqz
uses an FFT-based algorithm to calculate the Z-transform frequency
response of a digital filter. Specifically, the statement
[h,w] = freqz(b,a,p)
returns the p-point complex frequency response, H(e^{jω}), of the digital filter.
$$H({e}^{j\omega})=\frac{b(1)+b(2){e}^{-j\omega}+\mathrm{...}+b(n+1){e}^{-j\omega n}}{a(1)+a(2){e}^{-j\omega}+\mathrm{...}+a(m+1){e}^{-j\omega m}}$$
In its simplest form, freqz
accepts the filter
coefficient vectors b
and a
,
and an integer p
specifying the number of points
at which to calculate the frequency response. freqz
returns
the complex frequency response in vector h
, and
the actual frequency points in vector w
in rad/s.
freqz
can accept other parameters, such as
a sampling frequency or a vector of
arbitrary frequency points. The example below finds the 256-point
frequency response for a 12th-order Chebyshev Type I filter. The call
to freqz
specifies a sampling frequency fs
of
1000 Hz:
[b,a] = cheby1(12,0.5,200/500); [h,f] = freqz(b,a,256,1000);
Because the parameter list includes a sampling frequency, freqz
returns
a vector f
that contains the 256 frequency points
between 0 and fs/2
used in the frequency response
calculation.
Note This toolbox uses the convention that unit frequency is the Nyquist frequency, defined as half the sampling frequency. The cutoff frequency parameter for all basic filter design functions is normalized by the Nyquist frequency. For a system with a 1000 Hz sampling frequency, for example, 300 Hz is 300/500 = 0.6. To convert normalized frequency to angular frequency around the unit circle, multiply by π. To convert normalized frequency back to hertz, multiply by half the sample frequency. |
If you call freqz
with no output arguments,
it plots both magnitude versus frequency and phase versus frequency.
For example, a ninth-order Butterworth lowpass filter with a cutoff
frequency of 400 Hz, based on a 2000 Hz sampling frequency, is
[b,a] = butter(9,400/1000);
To calculate the 256-point complex frequency response
for this filter, and plot the magnitude and phase with freqz
,
use
freqz(b,a,256,2000)
freqz
can also accept a vector of arbitrary
frequency points for use in the frequency response calculation. For
example,
w = linspace(0,pi); h = freqz(b,a,w);
calculates the complex frequency response at the frequency
points in w
for the filter defined
by vectors b
and a
.
The frequency points can range from 0 to 2π.
To specify a frequency vector that ranges from zero to your sampling
frequency, include both the frequency vector and the sampling frequency
value in the parameter list.
These examples show how to compute and display digital frequency responses.
Compute and display the magnitude response of the third-order IIR lowpass filter described by the following transfer function:
Express the numerator and denominator as polynomial convolutions. Find the frequency response at 2001 points spanning the complete unit circle.
b0 = 0.05634;
b1 = [1 1];
b2 = [1 -1.0166 1];
a1 = [1 -0.683];
a2 = [1 -1.4461 0.7957];
b = b0*conv(b1,b2);
a = conv(a1,a2);
[h,w] = freqz(b,a,'whole',2001);
Plot the magnitude response expressed in decibels.
plot(w/pi,20*log10(abs(h))) ax = gca; ax.YLim = [-100 20]; ax.XTick = 0:.5:2; xlabel('Normalized Frequency (\times\pi rad/sample)') ylabel('Magnitude (dB)')
Design an FIR bandpass filter with passband between and rad/sample and 3 dB of ripple. The first stopband goes from to rad/sample and has an attenuation of 40 dB. The second stopband goes from rad/sample to the Nyquist frequency and has an attenuation of 30 dB. Compute the frequency response. Plot its magnitude in both linear units and decibels. Highlight the passband.
sf1 = 0.1; pf1 = 0.35; pf2 = 0.8; sf2 = 0.9; pb = linspace(pf1,pf2,1e3)*pi; bp = designfilt('bandpassfir', ... 'StopbandAttenuation1',40, 'StopbandFrequency1',sf1,... 'PassbandFrequency1',pf1,'PassbandRipple',3,'PassbandFrequency2',pf2, ... 'StopbandFrequency2',sf2,'StopbandAttenuation2',30); [h,w] = freqz(bp,1024); hpb = freqz(bp,pb); subplot(2,1,1) plot(w/pi,abs(h),pb/pi,abs(hpb),'.-') axis([0 1 -1 2]) legend('Response','Passband','Location','South') ylabel('Magnitude') subplot(2,1,2) plot(w/pi,db(h),pb/pi,db(hpb),'.-') axis([0 1 -60 10]) xlabel('Normalized Frequency (\times\pi rad/sample)') ylabel('Magnitude (dB)')
Design a 3rd-order highpass Butterworth filter having a normalized 3-dB frequency of rad/sample. Compute its frequency response. Express the magnitude response in decibels and plot it.
[b,a] = butter(3,0.5,'high'); [h,w] = freqz(b,a); dB = mag2db(abs(h)); plot(w/pi,dB) xlabel('\omega / \pi') ylabel('Magnitude (dB)') ylim([-82 5])
Repeat the computation using fvtool
.
fvtool(b,a)
freqs
evaluates frequency
response for an analog filter defined by two input coefficient vectors, b
and a
. Its operation is similar to that
of freqz
; you can specify a number of frequency
points to use, supply a vector of arbitrary frequency points, and
plot the magnitude and phase response of the filter. This example
shows how to compute and display analog frequency responses.
Design a 5th-order analog Butterworth lowpass filter with a cutoff frequency of 2 GHz. Multiply by to convert the frequency to radians per second. Compute the frequency response of the filter at 4096 points.
n = 5;
f = 2e9;
[zb,pb,kb] = butter(n,2*pi*f,'s');
[bb,ab] = zp2tf(zb,pb,kb);
[hb,wb] = freqs(bb,ab,4096);
Design a 5th-order Chebyshev Type I filter with the same edge frequency and 3 dB of passband ripple. Compute its frequency response.
[z1,p1,k1] = cheby1(n,3,2*pi*f,'s');
[b1,a1] = zp2tf(z1,p1,k1);
[h1,w1] = freqs(b1,a1,4096);
Design a 5th-order Chebyshev Type II filter with the same edge frequency and 30 dB of stopband attenuation. Compute its frequency response.
[z2,p2,k2] = cheby2(n,30,2*pi*f,'s');
[b2,a2] = zp2tf(z2,p2,k2);
[h2,w2] = freqs(b2,a2,4096);
Design a 5th-order elliptic filter with the same edge frequency, 3 dB of passband ripple, and 30 dB of stopband attenuation. Compute its frequency response.
[ze,pe,ke] = ellip(n,3,30,2*pi*f,'s');
[be,ae] = zp2tf(ze,pe,ke);
[he,we] = freqs(be,ae,4096);
Plot the attenuation in decibels. Express the frequency in gigahertz. Compare the filters.
plot(wb/(2e9*pi),mag2db(abs(hb))) hold on plot(w1/(2e9*pi),mag2db(abs(h1))) plot(w2/(2e9*pi),mag2db(abs(h2))) plot(we/(2e9*pi),mag2db(abs(he))) axis([0 4 -40 5]) grid xlabel('Frequency (GHz)') ylabel('Attenuation (dB)') legend('butter','cheby1','cheby2','ellip')
The Butterworth and Chebyshev Type II filters have flat passbands and wide transition bands. The Chebyshev Type I and elliptic filters roll off faster but have passband ripple. The frequency input to the Chebyshev Type II design function sets the beginning of the stopband rather than the end of the passband.