You can often formulate the mathematical system you are modeling in several ways. Choosing the best-form mathematical model allows the simulation to execute faster and more accurately. For example, consider a simple series RLC circuit.

According to Kirchoff's voltage law, the voltage drop across this circuit is equal to the sum of the voltage drop across each element of the circuit.

$${V}_{AC}={V}_{R}+{V}_{L}+{V}_{C}$$

$${V}_{AC}=Ri+L\frac{di}{dt}+\frac{1}{C}{\displaystyle {\int}_{-\infty}^{t}i(t)dt}$$

You can model this system in Simulink^{®} by solving for either
the resistor voltage or inductor voltage. Which you choose to solve
for affects the structure of the model and its performance.

Solving the RLC circuit for the resistor voltage yields

$$\begin{array}{l}{V}_{R}=Ri\\ Ri={V}_{AC}-L\frac{di}{dt}-\frac{1}{C}{\displaystyle {\int}_{-\infty}^{t}i(t)dt}\end{array}$$

The following diagram shows this equation modeled in Simulink where * R* is

`70`

, `0.00003`

,
and `0.04`

. The resistor
voltage is the sum of the voltage source, the capacitor voltage, and
the inductor voltage. You need the current in the circuit to calculate
the capacitor and inductor voltages. To calculate the current, multiply
the resistor voltage by a gain ofThis formulation contains a Derivative block associated with the inductor. Whenever possible, you should avoid mathematical formulations that require Derivative blocks as they introduce discontinuities into your system. Numerical integration is used to solve the model dynamics though time. These integration solvers take small steps through time to satisfy an accuracy constraint on the solution. If the discontinuity introduced by the Derivative block is too large, it is not possible for the solver to step across it.

In addition, in this model the Derivative, Sum, and two Gain blocks create an algebraic loop. Algebraic loops slow down the model's execution and can produce less accurate simulation results. See Algebraic Loops for more information.

To avoid using a Derivative block, formulate the equation to solve for the inductor voltage.

$$\begin{array}{l}{V}_{L}=L\frac{di}{dt}\\ L\frac{di}{dt}={V}_{AC}-Ri-\frac{1}{C}{\displaystyle {\int}_{-\infty}^{t}i(t)dt}\end{array}$$

The following diagram shows this equation modeled in Simulink.
The inductor voltage is the sum of the voltage source, the resistor
voltage, and the capacitor voltage. You need the current in the circuit
to calculate the resistor and capacitor voltages. To calculate the
current, integrate the inductor voltage and divide by* L*.
Calculate the capacitor voltage by integrating the current and dividing
by *C*. Calculate the resistor voltage by multiplying
the current by a gain of *R*.

This model contains only integrator blocks and no algebraic loops. As a result, the model simulates faster and more accurately.

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