Documentation

This is machine translation

Translated by Microsoft
Mouseover text to see original. Click the button below to return to the English verison of the page.

Note: This page has been translated by MathWorks. Please click here
To view all translated materals including this page, select Japan from the country navigator on the bottom of this page.

Finding Steady-State Points

The Simulink® trim function uses a model to determine steady-state points of a dynamic system that satisfy input, output, and state conditions that you specify. Consider, for example, this model, called ex_lmod.

You can use the trim function to find the values of the input and the states that set both outputs to 1. First, make initial guesses for the state variables (x) and input values (u), then set the desired value for the output (y).

x = [0; 0; 0];
u = 0;
y = [1; 1];

Use index variables to indicate which variables are fixed and which can vary.

ix = [];      % Don't fix any of the states
iu = [];      % Don't fix the input
iy = [1;2];   % Fix both output 1 and output 2

Invoking trim returns the solution. Your results might differ because of roundoff error.

[x,u,y,dx] = trim('lmod',x,u,y,ix,iu,iy)

x =
   0.0000
   1.0000
   1.0000
u =
   2
y =
   1.0000
   1.0000
dx =
   1.0e-015 *
    -0.2220
    -0.0227
     0.3331

Note that there might be no solution to equilibrium point problems. If that is the case, trim returns a solution that minimizes the maximum deviation from the desired result after first trying to set the derivatives to zero. For a description of the trim syntax, see trim.

See Also

Was this topic helpful?