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linalg::setRow

Change a row of a matrix

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Syntax

linalg::setRow(A, p, r)

Description

linalg::setRow(A, p, r) returns a copy of the matrix A with the p-th row replaced by the row vector .

If r is a list with at most n elements, then r is converted into a row vector. An error message is returned if the conversion is not possible (e.g., if an element of the list cannot be converted into an object of the component ring of A; see Example 2).

Examples

Example 1

We define a matrix over the rationals:

MatQ := Dom::Matrix(Dom::Rational): 
A := MatQ([[1, 2], [3, 2]])

and replace the 2nd row by the 1×2 zero vector:

linalg::setRow(A, 2, MatQ(1, 2, [0, 0]))

Example 2

We create the 2×4 zero matrix over 6:

B := Dom::Matrix(Dom::IntegerMod(6))(2, 4)

and replace the 2nd row by the vector (1, - 1, 1, - 1). We give the row vector in form of a list. Its elements are converted implicitly into objects of the component ring of B:

linalg::setRow(B, 2, [1, -1, 1, -1])

The following input leads to an error message because the number can not be converted into an object of type Dom::IntegerMod(6):

linalg::setRow(B, 1, [1/3, 0, 1, 0])
Error: The row vector is invalid. [linalg::setRow]

Parameters

A

An m×n matrix of a domain of category Cat::Matrix

r

A row vector or a list that can be converted into a row vector the domain Dom::Matrix(R), where R is the component ring of A (a row vector is a 1 ×n matrix)

Return Values

Matrix of the same domain type as A.

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