Merging two ordered lists
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listlib::merge(list1, list2) merges both
lists into one list.
With the third optional argument a function can be given that
compare the elements of the lists and therewith determines the order
of the elements. The given function is called with two elements and
have to return
TRUE, if the two elements are in
the right order, otherwise
FALSE (see next paragraph).
The given function is called step by step with an element of
the first list as first argument and an element of the second list
as second argument, until it returns
FALSE. Then the element
of the second list is inserted into the first list in front of
the last proved element (see Example 2).
The lists must be ordered with regard to the order function, otherwise the elements could be inserted at the wrong place.
If no third argument is given the function
_less is used. If no order of the elements
with regard to
defined, a function must be given, otherwise an error appears. The
can be used.
Merging two ascending ordered lists:
listlib::merge([1, 3, 5, 7], [2, 4, 6, 8])
Merging two descending ordered lists:
listlib::merge([7, 5, 3, 1], [8, 6, 4, 2], _not@_less)
The following example shows, how expressions can be ordered
by a user defined priority. This order is given by the function named
which returns a smaller number, when the expression has a type with
priority := X -> contains(["_power", "_mult", "_plus"], type(X)): priority(x^2), priority(x + 2)
the both given arguments are in the right order, i.e., the first argument
has a higher (or equal) priority than the second argument:
sortfunc := (X, Y) -> bool(priority(Y) > priority(X)): sortfunc(x^2, x + 2), sortfunc(x + 2, x*2)
Now the both lists are merged with regard to the given priority:
listlib::merge([x^y, x*2, -y], [x^2, x*y, x + y], sortfunc)
delete priority, sortfunc:
A MuPAD® list
A function that determines the merging order
Ordered list that contains the elements of both lists