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Sum of digits of an integer

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numlib::sumOfDigits(n, <base>)


numlib::sumOfDigits(n, base) computes the sum of digits of n in the given base base); if the base is not given, it defaults to 10.

The sum of digits may be larger than the base. For certain purposes (testing divisibility by b - 1, where b is the base), it may be useful to apply numlib::sumOfDigits over and over to the result. This is not done automatically. See Example 2.


Example 1

We compute the decimal and the binary sum of digits of 11:

numlib::sumOfDigits(11), numlib::sumOfDigits(11, 2)

Example 2

We want to test whether 9 divides a given number, using the school method:

n:= 24373463462374324: 
repeat n:= numlib::sumOfDigits(n); print(n) until n < 10 end: 
delete n:

This only makes sense for demonstration purposes, as the following command achieves the same but much faster:

24373463462374324 mod 9



Non-negative integer


Integer greater than one

Return Values

Non-negative integer

See Also

MuPAD Functions

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