This is machine translation

Translated by Microsoft
Mouseover text to see original. Click the button below to return to the English verison of the page.

Note: This page has been translated by MathWorks. Please click here
To view all translated materals including this page, select Japan from the country navigator on the bottom of this page.

Compute Bidirectional Limits

Suppose, you have a function f(x). The value C is a limit of the function f(x) at x = x0:


MuPAD® provides the limit command for computing limits. When computing a limit for a variable approaching 0, you can omit specifying x0. By default, the limit command assumes x0 = 0:

limit(sin(x)/x, x = 0);
limit((1 - cos(x))/x, x)

    Note:   Avoid computing limits for floating-point arguments.

If you use floating-point numbers as the parameters of limit, the round-off error can completely change the result. For example, a small error in the following example with the floating-point parameter changes the result from a rational number to the floating-point infinity:

limit((sin(x) - x)/x^3, x = 0);
limit((1.000001*sin(x) - x)/x^3, x = 0)

Was this topic helpful?