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Assign Temporary Values to Parameters |

Use temporary assumptions to specify that an object holds mathematical
properties for a particular calculation. Temporary assumptions also
help you narrow a general solution and get specific solutions. For
example, the following equation describes linear motion with constant
acceleration:
.
Here, `r` is the distance the object travels, *r*_{0} is
the initial distance, *v*_{0} is
the initial velocity, `a` is the constant acceleration,
and `t` is the time of travel. If you know all other
parameters and want to calculate the time that the object was moving,
solve the equation for the variable `t`:

t = solve(r = r_0 + v_0*t + a*t^2/2, t)

Suppose, you want to keep the general solution for all possible
cases of the linear motion with constant acceleration. You also want
to derive several special cases of this motion and get particular
solutions for these cases. For example, one of the objects you consider
moves with constant velocity. Derive the solution for this object
from the general solution for the time of the motion by assuming the
acceleration `a = 0`:

t = solve(r = r_0 + v_0*t + a*t^2/2, t) assuming a = 0 and r > r_0 and v_0 > 0

The assumption `a = 0` holds true only for
this particular call to `solve`.
The assumption does not affect other calculations:

is(a = 0)

If you set an assumption in the form of an inequality, both
sides of an inequality should represent real values. Inequalities
with complex numbers are invalid because the field of complex numbers
is not an ordered field. For example, if you try to use the following
assumption, MuPAD^{®} returns an error:

y + 1 assuming y > 2*I

Error: Assumptions are inconsistent. [property::_assume]

You can use complex values in assumptions presented in forms of equations:

y + 1 assuming y = 2*I

To solve the linear motion equation for particular values of the parameters, assign the values to the parameters:

r := 4: r_0 := 0: v_0 := 3: a := 2: t = solve(r = r_0 + v_0*t + a*t^2/2, t) assuming t > 0

If you use assignments, MuPAD evaluates variables to their values in all further computations:

r, r_0, v_0, a

To be able to reuse the variables in further computations, use
the `delete` command:

delete r, r_0, v_0, a

Using assumptions, you can temporarily assign values to the parameters. For example, solve the equation for the following values:

t = solve(r = r_0 + v_0*t + a*t^2/2, t) assuming r = 4 and r_0 = 0 and v_0 = 3 and a = 2 and t > 0

The variables remain free for further calculations because temporary assumptions do not hold true:

r, r_0, v_0, a, t

If assumptions contain linear equations with one variable, MuPAD solves these equations, inserts the solutions into the expression, and then evaluates the expression:

r = r_0 + v_0*t + a*t^2/2 assuming a + 5 = 5 and 2*v_0 + 4 = 14 and t = 3 and r_0 = 0

The `assuming` command
temporarily overwrites all permanent assumptions set on an object:

assume(z in R_); z assuming z = -2*I

After evaluating the statement with a temporary assumption, MuPAD reinstates the permanent assumption:

is(z in R_)

See how to use temporary assumptions in combination with permanent assumptions in Using Temporary Assumptions on Top of Permanent Assumptions.

Suppose you set permanent assumptions on a MuPAD object.
If you evaluate the object with a temporary assumption set by the `assuming` command, MuPAD ignores
the permanent assumptions in this evaluation:

assume(x in R_); solve(x^3 + x = 0, x) assuming (x <> 0)

To use permanent assumptions and a temporary assumption together,
add the temporary assumption using the `assumingAlso` command:

assume(x in R_); solve(x^3 + x = 0, x) assumingAlso (x <> 0)

When you use temporary assumptions on top of the permanent ones, always check that the assumptions do not contradict each other. Contradicting assumptions can lead to inconsistent and unpredictable results. In some cases, MuPAD detects conflicting assumptions and issues the following error:

assume(x < 0); x assumingAlso (x > 0);

Error: Assumptions are inconsistent. [property::_assume]

MuPAD does not guarantee to detect contradicting assumptions:

assume(x, Type::Even); x assumingAlso (x + 1, Type::Even)

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