Sort elements of symbolic vectors or matrices

`[`

shows the indices that each element
of `Y`

,`I`

] =
sort(___)`Y`

had in the original vector or matrix `X`

.

If `X`

is an `m`

-by-`n`

matrix
and you sort elements of each column (`dim`

```
=
2
```

), then each column of `I`

is a permutation
vector of the corresponding column of `X`

, such
that

for j = 1:n Y(:,j) = X(I(:,j),j); end

If `X`

is a two-dimensional matrix, and
you sort the elements of each column, the array `I`

shows
the row indices that the elements of `Y`

had in
the original matrix `X`

. If you sort the elements
of each row, `I`

shows the original column indices.

By default, `sort`

sorts
the element of a vector or a matrix in ascending order.

Sort the elements of the following symbolic vector:

syms a b c d e sort([7 e 1 c 5 d a b])

ans = [ 1, 5, 7, a, b, c, d, e]

To find the indices that each element of a
new vector or matrix `Y`

had in the original vector
or matrix `X`

, call `sort`

with
two output arguments.

Sort the matrix `X`

returning the matrix of
indices that each element of the sorted matrix had in `X`

:

X = sym(magic(3)); [Y, I] = sort(X)

Y = [ 3, 1, 2] [ 4, 5, 6] [ 8, 9, 7] I = 2 1 3 3 2 1 1 3 2

When sorting elements of a matrix, `sort`

can
work along the columns or rows of that matrix.

Sort the elements of the following symbolic matrix:

X = sym(magic(3))

X = [ 8, 1, 6] [ 3, 5, 7] [ 4, 9, 2]

By default, the `sort`

command sorts elements
of each column:

sort(X)

ans = [ 3, 1, 2] [ 4, 5, 6] [ 8, 9, 7]

To sort the elements of each row, use set the value of the `dim`

option
to `2`

:

sort(X,2)

ans = [ 1, 6, 8] [ 3, 5, 7] [ 2, 4, 9]

`sort`

can sort the elements
of a vector or a matrix in descending order.

Sort the elements of this vector in descending order:

syms a b c d e sort([7 e 1 c 5 d a b], 'descend')

ans = [ e, d, c, b, a, 7, 5, 1]

Sort the elements of each column of this matrix `X`

in
descending order:

X = sym(magic(3)) sort(X,'descend')

X = [ 8, 1, 6] [ 3, 5, 7] [ 4, 9, 2] ans = [ 8, 9, 7] [ 4, 5, 6] [ 3, 1, 2]

Now, sort the elements of each row of `X`

in
descending order:

sort(X, 2, 'descend')

ans = [ 8, 6, 1] [ 7, 5, 3] [ 9, 4, 2]

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