filling a internal value of a matrix

1 view (last 30 days)
Hi I have the following matrix
I=
0 1 0 0
0 0 1 1
0 1 0 0
0 0 1 0
I want the following output:
0 1 0 0
0 1 1 1
0 1 1 0
0 0 1 0
Is there any easy way to do that,easily?
Thanks

Accepted Answer

Matt Fig
Matt Fig on 26 Jun 2011
This function will help you: FINDSUBMAT. Here is an example:
I=[0 1 0 0
0 0 1 1
0 1 0 0
1 0 0 0
0 0 1 0
1 0 0 0
0 0 1 0];
idx = findsubmat(I,[1 0 1]'); % Available at the above link...
I(idx+1) = 1
I =
0 1 0 0
0 1 1 1
0 1 0 0
1 0 0 0
1 0 1 0
1 0 1 0
0 0 1 0

More Answers (1)

Paulo Silva
Paulo Silva on 26 Jun 2011
I(6)=1;
I(11)=1;
or
I([6 11])=1
  3 Comments
Walter Roberson
Walter Roberson on 26 Jun 2011
Please give an example of the desired output matrix.
Mohammad Golam Kibria
Mohammad Golam Kibria on 26 Jun 2011
I=
0 1 0 0
0 0 1 1
0 1 0 0
0 0 0 0
0 0 1 0
0 0 0 0
0 0 1 0
output:
0 1 0 0
0 1 1 1
0 1 0 0
0 0 0 0
0 0 1 0
0 0 1 0
0 0 1 0
This is an example, your previous code will work for
this simple matrix, but in case when my matrix is larger
and I dont know where this type of pattern
1
0
1
exists and then replace the middle 0 to 1 as above

Sign in to comment.

Categories

Find more on Data Types in Help Center and File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!