how can I solve transcendental equation?
2 views (last 30 days)
Show older comments
I want to solve the given equation in matlab to find the value of beta but getting error. I am posting the code and error below.
Thanks in advance.
n1=1.77;
n2=1.45;
d=1e-6;
lambda = 1e-6;
ko = 2*pi/lambda;
A=(ko*n1)^2;
B=(ko*n2)^2;
syms beta;
s = 'sqrt(A-beta^2)*(d/2)*tan(sqrt(A-beta^2)*d/2)=sqrt(beta^2-B)*(d/2)';
solve (s);
Error:
Error using solve>processString (line 337) ' sqrt(A-beta^2)*(d/2)*tan(sqrt(A-beta^2)*d/2)=sqrt(beta^2-B)*(d/2) ' is not a valid expression or equation.
Error in solve>getEqns (line 267) eqns = processString(eqns, v, vc);
Error in solve (line 150) [eqns,vars,options] = getEqns(varargin{:});
Error in transcendetal (line 9) solve (s);
0 Comments
Answers (1)
Walter Roberson
on 4 Nov 2013
s = sqrt(A-beta^2)*(d/2)*tan(sqrt(A-beta^2)*d/2) - sqrt(beta^2-B)*(d/2);
0 Comments
See Also
Categories
Find more on Symbolic Math Toolbox in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!