HELP on computing an array from the previously given array with two adjustments.

hmm so i have an array which is A = [3,5,-4;-8,-1,33;-17,6,-9], and i have to compute an array B by computing the natural logarithm of elements of A whose value is no less than 1, but adding 20 to all the other elements. I also have to use a "for" loop with conditional statements to make B. So far i have,

A=[ 3, 5, -4; -8,-1, 33; -17, 6, -9]; 
B=zeros(size(A)); 
for i=1:size(A,1) 
for j=1:size(A,2) 
if(A(i,j)>=1) 
B(i,j)=A(i,j)+20 
else 
B(i,j)=log(A(i.j)) 
end 
end 
end

this does not work apparantly, can you guys help me with this! its bugging me really bad!

Answer 1

[Walter Roberson]

Add 20 to the other elements, not the ones that are "no less than 1"

And log(A(i.j)) should be log(A(i,j))

[Jay]

how do i add 20 to the other elements? do i switch it around? Thanks!

[Jay]

i tried switching it around, only to get an error saying " A = | Error: Expression or statement is incomplete or incorrect."