pixel by pixel comparison of images
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hello I am working with gabor filter. I have 12 images with different orientations which is output by gabor filter.I want to perform pixel by pixel comparison of images and find the maximum response image. maximum response of image is the image which has the highest pixel value other than all the images .can anybody tell me how do i do it. I have a small piece of code.
for n=1:N
count = 1;
gb = gabor_fn(bw,gamma,psi(1),lambda,theta);%...
figure;
imshow(gb);
theta = theta + pi/N;
end
Accepted Answer
More Answers (1)
Image Analyst
on 10 Nov 2013
Something like this perhaps:
theMaxValues = zeros(1, N);
theta = 0; % whatever...
for n=1:N
gb = gabor_fn(bw,gamma,psi(1),lambda,theta(n));
theMaxValues(n) = max(gb(:));
figure;
imshow(gb);
theta(n+1) = theta(n) + pi/N;
end
[overallMax, index] = max(theMaxValues);
thetaOfMax = theta(index);
final_gb = gabor_fn(bw,gamma,psi(1),lambda,thetaOfMax);
5 Comments
vidya
on 11 Nov 2013
Image Analyst
on 11 Nov 2013
You passed in theta - the whole array - not the theta(n) like I told you to. Why? You will get an error, like you did, because evidently it wants a scalar, not a whole array.
vidya
on 12 Nov 2013
Image Analyst
on 12 Nov 2013
I don't have your code so I can't go much more. Even if I did, I probably wouldn't have time. Please review this: http://blogs.mathworks.com/videos/2012/07/03/debugging-in-matlab/ and you will be able to solve it yourself. Also please make yourself aware how dot operators work - when and why you use them. There is a difference between matrix multiplication of two matrices, and multiplication of those two matrices element-by-element. You can matrix multiply a n*m matrix by a m*n matrix, but you can't do an element by element multiplication if n is not equal to m. Similarly you can dot multiply element-by-element an m*n matrix by another n*m matrix, but you can't do a matrix multiplication of those matrices. Make very sure you understand those concepts and operators very well.
vidya
on 13 Nov 2013
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