please i want to know where is the mistake in the this code

Part 1: Range and Time of Flight of a Cannonball

>> [R,tof] = Q1_STNO(v,theta);

>>G=9.81;

>>R=Q1_0123456(v,theta);

>>R=(v^2)*sin(2*theta)/g;

>>tof=Q1_0123456(v,theta);

>>tof=2*v*sin(theta)/g;

>>disp([‘Answer = ‘ num2str(R)’]);

>>disp([‘Answer = ‘ num2str(theta)’]);

part2

>> [hMaxAir,hMaxVac] = Q2_STNO(v,theta);

>> [x,y,range] = trajectoryInAir(v,theta);

>> [x,y,range] = trajectoryInAir(100,40); 

>> plot(x,y); 

>>   axis equal;

Targeting the cannonball

>> [vmin,vmax] = Q3_STNO(X,W);

>>vmin=Q3_0123456(X,W);

>>vmin=[x,y,range] = trajectoryInAir(0.1,0.5);

>>vmax=[x,y,range] = trajectoryInAir(0.5,1);

>>plot(x,y);

>>axis equal;

A falling cannonball

>> v = Q4_STNO(m,d,tx);

>>d=0.47*0.5*1.2*6;

>> [v,vTerminal] = Q4e_STNO(m,d,tx);

please i want to know why this code i wrote it and not work any one can help me with it ????

[Grzegorz Knor]

But none of us know what denote Q1_STNO, Q1_0123456 etc. And what is your error?

[mohammad Mohsen]

The syntax of your function should take the form

>> [R,tof] = Q1_STNO(v,theta);

where STNO should be replaced by your student number, v is the launch velocity (m/s), theta is the launch angle (degrees (not radians) from the ground), R is the range (m), and tof is the time of flight (s).

[Walter Roberson]

Okay. Now what error message are you encountering? Please show the error traceback.

[mohammad Mohsen]

Error using part1 (line 2) Not enough input arguments.

[mohammad Mohsen]

Undefined function or variable 'v'.

Error in PART2 (line 1) [hMaxAir,hMaxVac] = Q2_STNO(v,theta);

[mohammad Mohsen]

Error: File: part3.m Line: 3 Column: 18 The expression to the left of the equals sign is not a valid target for an assignment.

[mohammad Mohsen]

Undefined function or variable 'm'.

Error in part4 (line 1) v = Q4_STNO(m,d,tx);

Answer 1

[Walter Roberson]

You have

>>R=Q1_0123456(v,theta);

>>R=(v^2)*sin(2*theta)/g;

>>tof=Q1_0123456(v,theta);

>>tof=2*v*sin(theta)/g;

In both of those, you call Q1_0123456 to calculate a value, but you then immediately overwrite the value with your next command.

When you have a function of the form

[A, B] = C(D)

then you cannot "take turns" producing A or B from the function,

A = C(D);
B = C(D);

That second call will not produce the second output: it will recalculate the first output and replace B with that first output.

If your function is producing two outputs, you need to calculate the both at one time,

[A, B] = C(D);