1.1 + 0.1 == 1.2 returns false
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Very strange.
Apparently this is related to the precision of the double type as
1.1 + 0.1 - 1.2 = 2.2204e-16
What can I do to counter this behavior? Thanks!
1 Comment
James Tursa
on 31 Jan 2014
As a learning aid you can use this FEX submission to see the exact numbers involved:
E.g., for your example,
>> num2strexact(1.1)
ans =
1.100000000000000088817841970012523233890533447265625
>> num2strexact(0.1)
ans =
0.1000000000000000055511151231257827021181583404541015625
>> num2strexact(1.1+0.1)
ans =
1.20000000000000017763568394002504646778106689453125
>> num2strexact(1.2)
ans =
1.1999999999999999555910790149937383830547332763671875
Accepted Answer
Image Analyst
on 13 Jan 2014
Edited: Image Analyst
on 13 Jan 2014
See the FAQ: http://matlab.wikia.com/wiki/FAQ#Why_is_0.3_-_0.2_-_0.1_.28or_similar.29_not_equal_to_zero.3F It has strategies to deal with this situation, such as comparing the value to a tolerance.
% instead of a == b
% use:
areEssentiallyEqual = abs(a-b) < tol
% for some small value of tol relative to a and b
% perhaps defined using eps(a) and/or eps(b)
2 Comments
Roger Stafford
on 31 Jan 2014
Edited: Roger Stafford
on 31 Jan 2014
In both matlab and on my calculator these quantities come out unequal:
(sqrt(2))^2 ~= 2
(3/14+15/14)+3/14 ~= 1.5
The reason is quite clear. The quantities on the left hand side involve fractional values that cannot be represented exactly either on matlab's computer or on a decimal calculator. But when it comes to
11/10+1/10 and 12/10,
as in the case you mentioned, the calculator has them exactly equal but matlab doesn't. Why is that? It is because the calculator is using decimal digits and the computer is using binary digits - even though matlab normally displays numbers in decimal form, it is actually performing the computation with numbers in binary form. There is no way matlab could be programmed to obtain an exact equality in all such cases when division by something other than powers of 2 are involved. For that reason you cannot expect exact equality where, for example, division by 10 is involved. This is the binary computing world you have entered.
More Answers (2)
Mischa Kim
on 13 Jan 2014
Edited: Mischa Kim
on 13 Jan 2014
MATLAB is a numerical software tool, not an algebraic one. What you are seeing there is the numerical accuracy measure called eps. In other words, this is as accurate as your results will get.
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