## Conditional plotting, changing color of line based on value.

### S Tajik (view profile)

on 10 Feb 2011
Latest activity Commented on by Arijit

### Arijit (view profile)

on 5 Mar 2014

I've got a live stream of data coming to MATLAB. MATLAB does all the calculations and plotting just fine. The only problem is the colour of the plot lines.

I would like to have the plot line change colour automatically when is above or below a set number.

For example if my data is above 0 the plot line would be green and if below 0 the plot line would be red. So after a while when many data points were generated and plotted on the MATLAB figure, I'd like to see all lines above 0 to be green and all lines below 0 in red.

Arijit

### Arijit (view profile)

on 5 Mar 2014

I like to mark in a stream time series data when data value equals to a threshold. Whenever such value is reached in a streaming time series plot the marker will appear and then streaming will go on with the marker. I have modified code from http://www.mathworks.in/matlabcentral/answers/87466-real-time-plot-from-streaming-data as:

t = 0 ; x = 0 ; startSpot = 0; interv = 1000 ; % considering 1000 samples step = 0.1 ; % lowering step has a number of cycles and then acquire more data while ( t <interv ) b = sin(t)+5; x = [ x, b ]; plot(x) ; if ((t/step)-500 < 0) startSpot = 0; else startSpot = (t/step)-500; end axis([ startSpot, (t/step+50), 0 , 10 ]); grid t = t + step; drawnow; pause(0.01) end

But this is not working as intended????

## Products

### Matt Fig (view profile)

on 10 Feb 2011

Perhaps you mean something like this:

```x = -10:.01:10;
y = sin(x);
idx = y<=0;
plot(x(idx),y(idx),'r*',x(~idx),y(~idx),'b*')
```

EDIT

Simulate data coming in one piece at a time. Use a FOR loop as the simulated data retrieval mechanism.

```x = -10:.01:10;
for ii = 1:length(x)
y(ii) = sin(x(ii));  % Data point ii has come in.
```
```      if y(ii)<0
c = 'r*';
else
c = 'b*';
end```
```      plot(x(ii),y(ii),c)
hold on
end```

Matt Fig

### Matt Fig (view profile)

on 10 Feb 2011

(Thanks Doug!)
That would depend on how the data is coming in. If it is coming in one piece at a time, do like in my edit above.

S Tajik

### S Tajik (view profile)

on 10 Feb 2011

data coming in live (numerical) and then used to do some calculations on it (find the high and low of a certain period).
once the calculations are done all the NEW data are stored in vectors. and feeded into the plot diagram. Ive been trying to use your method to do so but so far nothing. in your example you used y value as a condition, what I need is as follow:
if price>myIndicator
plot price green
if price<myIndicator
plot price red

hope that explains a bit more
thanks for the help.

Matt Fig

### Matt Fig (view profile)

on 10 Feb 2011

Notice I did not work on the whole vector with an IF statement! When I was working with the whole vector, I used a logical index instead. Look at the idx value in my first post and see how I used it.

### Seth DeLand (view profile)

on 10 Feb 2011

Here's a way to do it that splits the data up into 2 lines and then plots them both. Overlapping points are set to NaN so that they are not plotted.

```% Your Data
```
```x = 0:0.01:10;
y = sin(x);
```
```% Level for Color Change
```
```lev = 0.2;
```
```% Find points above the level
```
```aboveLine = (y>=lev);
```
```% Create 2 copies of y
```
```bottomLine = y;
topLine = y;
```
```% Set the values you don't want to get drawn to nan
```
```bottomLine(aboveLine) = NaN;
```
```topLine(~aboveLine) = NaN;
```
```plot(x,bottomLine,'r',x,topline,'g');
```

Doug Hull

### Doug Hull (view profile)

on 10 Feb 2011

Used super powers to change this for my colleague, Seth.

S Tajik

### S Tajik (view profile)

on 10 Feb 2011

myx values are not stored in any vector as they can get very large and damp up the memory. they are just normal numeric data 1, 2 ,3 ,4 and so on. used as index.
my y values are however stored in a vector. when I use the solutions provided on this page I get the graph i want but it only plots dots and do not connect them together. I assume that is because my x value is not a vector.
any inputs will be much appreciated.

cheers

Walter Roberson

### Walter Roberson (view profile)

on 11 Feb 2011

plot(bottomLine,'r');
hold on;
plot(topline,'g')

### Vieniava (view profile)

on 10 Feb 2011

To control colour of any segment of plot you should use line()

```>> doc line
```

Walter Roberson

### Walter Roberson (view profile)

on 10 Feb 2011

That will not help any more than using plot(). line() has the same limitation, that any one line segment must be a single color.

### Matt Tearle (view profile)

on 11 Feb 2011

Maybe this is going overboard, but given your comment "but it only plots dots and do not connect them together", I'm guessing you're getting a lot of crossings of the cutoff value. So... here's a brute-force approach that actually interpolates between the crossings.

Because of what you said about size and memory, I tried to make it so that memory wouldn't be an issue. (So the code isn't as pretty as it probably could be.)

```x = 0:0.1:10;
y = sin(4*x);
clr = {'b','r'};
lev = -0.35;
```
```n = length(y);
idx = [0,find(sign(y(2:end)-lev)~=sign(y(1:end-1)-lev)),n];
nidx = length(idx);
```
```for k=2:nidx
x1 = idx(k-1)+1;
x2 = idx(k);
line(x1:x2,y(x1:x2),'color',clr{mod(k,2)+1},'marker','o')
if k<nidx
x1 = x2;
x2 = x1+1;
y1 = y(x1);
y2 = y(x2);
x0 = x1 + (lev-y1)/(y2-y1);
y0 = y1 + (x0-x1)*(y2-y1);
line([x1,x0],[y1,y0],'color',clr{mod(k,2)+1})
line([x0,x2],[y0,y2],'color',clr{mod(k+1,2)+1})
end
end
```

### Matt Tearle (view profile)

on 22 Feb 2011

Because I'm a dork, I made a function to do this. It's now available on File Exchange. You can contact me to find out where to send generous tips!