Warning: Colon operands should not be logical

kkjnkjn

Answer 1

[Walter Roberson]

at least one of the entries k(novtrls).endingAdjFixNum is of logical data type instead of numeric.

find(cellfun(@islogical, {k.endingAdjFixNum}))

to see which ones

Answer 2

[Image Analyst]

You forgot to put the error message so we know what line it's complaining about. Put this line before it bombs:

whos FixAdjEnd
k(novtrls).fixX
k(novtrls).fixY
k(novtrls).fixS
k(novtrls).fixE

and tell us what it says so that we have a better chance of helping you while doing this "blind" (i.e. with no data, small snippet of code that can't run, and no full error message).

[gradstudent1]

This code may not be the best to work with so I'm thinking of starting from scratch. The idea is that I need to extract all data within a subfield (arranged in a column), but instead of extracting every value in the column, I only want to extract the data from the first row up until the row corresponding to a number in a different subfield. ie: for the subfield FixX rather than extracting X=1:length(FixX) I would like to extract X=1:endingAdjFixNum

I'm sure the syntax is far off so any guidance would be appreciated

[Image Analyst]

See if this snippet helps:

structData.array = randi(9, [5,5]) % Define 2D array
structData.array % Report to command window.
structData.firstIndex = 2;
structData.lastIndex = 3
% Extract subarray
subArray = structData.array(:, structData.firstIndex : structData.lastIndex)

It shows how to extract a sub array out of an array where the array is one field of a structure, and the starting and ending columns are other members/fields of the structure.