plot parametric curves between xy-limits

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Ilya
Ilya on 22 Apr 2014
Edited: Ilya on 22 Apr 2014
I'm not sure if it's possible at all, but may be somebody knows the answer..
I have two parametric equations:
x=f(t)
y=g(t)
which describe some curve in XY plane. f(t) and g(t) are rational polynomial functions, i.e. the curve is an algebraic curve. The ezplot function of MATLAB allows to plot parametric curves for some values of parameter. Is it somehow possible to plot parametric curves for some values of x and y? Or we can only first find the plotting intervals of t by solving some inequalities, and then plot f(t) and g(t) on these intervals?
One solution could be implicitize the parametric curve (i.e. make it look like h(x,y)=0, thus eliminating t), but it is not easy to do in general case.
What is the best practical solution to my problem? I think that the problem is quite essential, and I'm not the only one who faces it.
  4 Comments
José-Luis
José-Luis on 22 Apr 2014
Edited: José-Luis on 22 Apr 2014
Which xy plane? x = 3, y = 2? Something else? Note that even then you might get nothing or only a bunch of points in said plane. Or do you want a three-dimensional plot? In that case I recommend you look at plot3().
Or do you want to project everything to a single plane? Then it is just a matter of setting one of your dimensions to a scalar and using plot().
I am sorry but what you want is not clear to me.
Ilya
Ilya on 22 Apr 2014
Edited: Ilya on 22 Apr 2014
I still try to clarify the thing by repeating only one small part of the question:
I have two parametric equations: x=f(t); y=g(t) which describe some curve in XY plane. I.e. two equation describe one curve, and this is called "parametric curve".
However, the question should seem clear to the users familiar with parametric curves and ezplot() function, which seems to allow setting limits on x and y for implicit curves f(x,y)=0, but not on parametric ones.
And, as I said, the solution may not exist in MATLAB or any other software.. I simply don't know, that's why I'm asking

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