How to assign a value to a cell nested in another cell

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Hi everyone,
I have a seemingly simple problem but can't seem to figure out. I have something like this P={'Face1','Face2','Scene1','Scene2'}. What I would like to do is to assign a value to each of the element in P and still preserve the element's identity. For instance, the values could be assigned like this: Face1=4*5, Face2=23*6, etc.
However, when I do P{1,1}=4*5 then P becomes {20,'Face2','Scene1','Scene2}.This is not what I want since I've lost Face1. I'd like to keep the identity of each cell so when I call D{1,1} I'll get Face1, and when I call Face1, I'll get 20.
I hope the question is clear. Does anyone have any suggestions?
Thanks!

Accepted Answer

Jan
Jan on 23 Apr 2014
This seems to be a magic question. What about this:
P = {'Face1','Face2','Scene1','Scene2'}
Face1 = 4*5
Or perhaps you want to use the string dynamically. Then using dynamic field names with structs is neat:
S.(P{1,1}) = 4*5;
disp(S)
S.Face1

More Answers (1)

Image Analyst
Image Analyst on 23 Apr 2014
I don't understand why you want this. Why do you? After all, the row and column are already numbers that uniquely identify every single element in your cell array . If you want just one number you could use sub2ind(). But I still don't know why .
  2 Comments
Thang  Le
Thang Le on 23 Apr 2014
My rationale for doing this is that the actual P has 72 elements. Also depending on the version of the experiment I have, the order of these elements may change from one subject to another. So I thought I could specify the order of the element with P={'Face1','Face2','Scene1' etc.} for each version. Next, I'd do the caculation later for each of the elements. And since there are 72 elements, I thought a loop might be appropriate. Thus, instead of specify Face1=4*5, Face2=etc. I could do something like this:
for i=1:length(P)
P{i,1}= whatever calculation is to be done
end
At the end, I'd like to get the mean of all the Face elements, mean of all the Scene elements.
Image Analyst
Image Analyst on 23 Apr 2014
Not sure I understand quite yet, but let me ask this first: Do you want P to be a 1-D array of cells, or a 2-D matrix of cells? You seem to have used it both ways.
And regarding your subject line about "a cell nested in another cell", does any of the cells in the array contain another cell ? Because to me, that's what nested means. If so, what's in the nested cell. Or do all the cells simply contain single, simple strings (character arrays)?
Have you read the FAQ on cells? http://matlab.wikia.com/wiki/FAQ#What_is_a_cell_array.3F I think it gives a good intuitive explanation of cells and cell arrays.

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