Can anyone please tell me what if the nargin function is doing? I've been trying to learn how to use matlab on my own. //thanx
function [m_hat,s2hat ] = yatzy(n)
for m = 1:n value = tillsfem(5); throws(m) = value;
end m_hat = mean(throws); s2hat = var(throws);
throw_max = max(throws); p = ; A = [0 1/6 1/36 1/216 1/1296; 0 5/6 10/36 15/216 25/1296; 0 0 25/36 80/216 250/1296; 0 0 0 120/216 900/1296; 0 0 0 0 120/1296]; e1 = [1 0 0 0 0]'; e5 = [0 0 0 0 1]'; p = zeros(throw_max, n); for m = 1:throw_max pm = e1'*A^m*e5; p(m) = pm; end
if nargin < 2 k = 1:throw_max; p = p*n; else p = p*n*throw_max/k; end figure(1); clf; hist(throws,k); hold on stem(1:throw_max,p,'r') title('number of throws to get 5 equal dice') legend('Numerical','Analytical') xlabel('Number of throws') ylabel('Frequency') hold off
fprintf(['Expected number of throws to get: %4.2f '... '(analytical)\n' ... ' %4.2f '... '(numerical)\n' ... 'Expected variance: %4.2f '... '(analytical)\n' ... ' %4.2f '... '(numerical)\n'], ... 191283/17248, m_hat, 12125651655/297493504, s2hat);
I just need help with explaining if nargin < 2 k = 1:throw_max; p = p*n; else p = p*n*throw_max/k;
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nargin means "number of arguments in". In the above code it looks pretty useless:
if nargin < 2 %do stuff end
nargin in this case can only be 0 or 1, since yatzy(n) only allows for one input argument, (n), or no input arguments, yatzy. If you call yatzy with two input arguments, e.g.
It will error out with something along the lines of "Error using yatzy, more input arguments than expected"
Now as for future reference, since you're learning: nargin is typically used for error checking and so you can have optional arguments, e.g:
let's write a program f that takes one or two input arguments with the 2nd being optional:
function out = f(x,y); if nargin==0 %user called >>f error('Not enough input arguments, 1 is required'); elseif nargin==1 %user called f(x) y = pi; end %if neither, user called f(x,y)
Here we've made sure the person enters at least one argument, x, if they entered a second one great! if not, the second one, y, = pi.
hi thank you for the answer, but could you explain the rest of the peace for me k = 1:throw_max; p = p*n; else p = p*n*throw_max/k; what k,n,p is? and what happens later i got this from a friend so is kinda hard for me to understand everything :)
It is likely a bad code. The function has only one input argument so nargin<2 is always true. If you try to provide more than one input arguments like yatzy(3,4), it will cause an error saying too many input arguments.
You do not need MATLAB to figure out what is going on. Just work through your code line by line with a pencil and paper.
function [m_hat,s2hat ] = yatzy(n)
At this point the only thing in memory is n.
for m = 1:n
now we do something n times. What do we do, well that is:
value = tillsfem(5);
Well is is not so clear since you haven't told us what tillsfem does. It looks like value could be anything. Oh wait, look,
throws(m) = value;
this means value must be a scalar. So we could actually write
throws(m) = tillsfem(5);
So now we have n and throws which is a nx1 array of something.
m_hat = mean(throws);
hmmm, I wonder what that does. Do you know what the command mean does? You can go to the online documentation and find out that mean takes the mean of an array and returns a scalar. So now you have n and m_hat which are a scalars and throws which is a nx1 array.
It is as easy as that. The nice about MATLAB is it does exactly what you tell it to do.
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