## Excluded Digits from vector

on 22 Aug 2014
Latest activity Commented on by Guillaume

on 22 Aug 2014

### the cyclist (view profile)

vector=[1 2 5 13 55 23 15],excluded dig=5 then out=[1 2 13 23] ,another example vector=[3 24 7 9 18 55 67 71],excluded dig=7 then out=[3 24 9 18 55]

the cyclist

### the cyclist (view profile)

on 22 Aug 2014

I posted this as a Cody problem . As you may know, Cody rewards brevity of code over all other things.

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### the cyclist (view profile)

on 22 Aug 2014

I expect there is a much cleaner method, but here is one that works:

```vector = [1 2 5 13 55 23 15];
exDigit = 5;
```
```v = vector;
hasDigit = false(1,numel(v));
```
```while max(v>=1)
hasDigit = hasDigit | mod(v,10)==exDigit;
v = floor(v/10);
end
```
```new_vector = vector(not(hasDigit))
```

### Guillaume (view profile)

on 22 Aug 2014
```str2num(regexprep(num2str(vector), sprintf('\\<\\d*%d\\d*\\>', digit), ''))
```

Is a neat one liner but may not be faster than the cyclist answer due to the conversion to/from string and the use of regular expression.

Guillaume

### Guillaume (view profile)

on 22 Aug 2014

Another potential method, faster than regexp but still slower than the cyclist's:

```vector(arrayfun(@(n) all(num2str(n)-'0' ~= digit), vector))
```
the cyclist

### the cyclist (view profile)

on 22 Aug 2014

I stole this solution and posted it to Cody. As I write this, it is the leader.

Guillaume

### Guillaume (view profile)

on 22 Aug 2014

What? No fair! I should so rightly be the leader! ;)

Ha! Beaten with a variant on my regexp one-line :)

### the cyclist (view profile)

on 22 Aug 2014

Here is a solution that came out of Cody. The inputs to the function are the vector v and the excluded digit d.

```function ans = digitRemove(v,d)
```
```I = [];
```
```for i = 1 : length(v)
if ~any(ismember( num2str(v(i)) - '0' , d))
I = [I i];
end
end
```
```v(I);
end
```

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