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Can MATLAB pass by reference?

Asked by Doug Hull on 18 Jan 2011

How does MATLAB deal with this?

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Doug Hull

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2 Answers

Answer by Doug Hull on 18 Jan 2011
Accepted answer

If you are attempting to use pass-by-reference to modify the input argument passed into a function, the answer to the question depends on whether the input is a handle object or a value object. The two types of objects are described in the Object-Oriented Programming

http://www.mathworks.com/access/helpdesk/help/techdoc/matlab_oop/brfylq3.html and Programming Fundamentals http://www.mathworks.com/access/helpdesk/help/techdoc/matlab_prog/brtm8si.html sections of the documentation. By default, objects (including matrices, arrays, etc. of the built-in data types) are value objects.

Handle objects do exhibit reference behavior when passed as function arguments; value objects do not. When you pass a handle object to a function, MATLAB still copies the value of the argument to the parameter variable in the function (with one bit of subtlety; see below.) However, all copies of a handle object refer to the same underlying object.

If a function modifies a handle object passed as an input argument, the modification affects the object referenced by both the original and copied handles. In this case, the function does not need to return the result to be reassigned.

If instead you are attempting to use pass-by-reference to avoid unnecessary copying of data into the workspace of the function you're calling, you should be aware that MATLAB uses a system commonly called "copy-on-write" to avoid making a copy of the input argument inside the function workspace until or unless you modify the input argument. If you do not modify the input argument, MATLAB will avoid making a copy. For instance, in this code:

function y = functionOfLargeMatrix(x)
y = x(1);

MATLAB will not make a copy of the input in the workspace of functionOfLargeMatrix, as x is not being changed in that function. If on the other hand, you called this function:

function y = functionOfLargeMatrix2(x)
x(2) = 2;
y = x(1);

then x is being modified inside the workspace of functionOfLargeMatrix2, and so a copy must be made.

For more information on this behavior, read this posting http://blogs.mathworks.com/loren/2006/05/10/memory-management-for-functions-and-variables/ on Loren Shure's blog.

[From the MATLAB FAQ of Ancient Times]

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Doug Hull
Answer by Marco on 18 Jul 2012

Is this also true for nested function calls? Cuz it seems like it only works for direct function calls. In my GUIDE gui I have a function (call it Fn_takesHandles) that takes in the figure handles and updates the axes, when called by callback functions directly works just as intended. However, I run into problems when the stack frame is not one-to-one. A callBack function calls a helper function called Auto which in turn calls Fn_takesHandles. In this case it does not work as intended. Any changes made to the figure handles by Fn_takesHandles is not persistent. How would you go about solving this problem?

Is there any way to declare pointers in matlab? Any help would be appreciated!!

1 Comment

Walter Roberson on 19 Jul 2012

There is no way to declare pointers in MATLAB.

Marco

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