What is the name of the tune that contains the frequency of f=494;440;​392;440;49​4;494;494?

Dear experts, I have a problem to ask.

....we have one-seconded sinusoidal wave with a decaying exponential envelope: t=[0; 1] f(t) = exp(-5t) sin(2*f0t): where fo=[494;440;392;440;494;494;494]; create seven signals with di fferent frequencies and concatenate them into signal array before play sound. By listening to the sound of this sequent wave, what is the name of the tune???...

Actually, I have listen to the sound, but I really can recognize the tune! So, someone help me please!!!

please help me as soon as possible....!!!

[Image Analyst]

Please give your MATLAB code to generate the signal. You have not done that yet. Or attach the wav file. Does the decay apply to each sound segment individually, or just to the 5 second sound all together?

[Davye Mak]

ok, the code that I wrote is like below:

fs=8e3; t=0:1/fs:1; f0=[494,440,392,440,494,494,494]; a=exp(-5*t); x1=a.*sin(2*pi*f0(1)*t); x2=a.*sin(2*pi*f0(2)*t); x3=a.*sin(2*pi*f0(3)*t); x4=a.*sin(2*pi*f0(4)*t); x5=a.*sin(2*pi*f0(5)*t); x6=a.*sin(2*pi*f0(6)*t); x7=a.*sin(2*pi*f0(7)*t); X=[x1,x2,x3,x4,x5,x6,x7]; sound(X,fs);

that it!!

[Matt Tearle]

From the frequencies alone you can see that the tune is clearly B-A-G-A-B-B-B... you couldn't figure it out from there? Pfft. I guess that's why you're an image analyst ;)

Answer 1

[Star Strider]

Mary Had A Little Lamb!

Reasonable approximation:

fo=[494;440;392;440;494;494;494];
f = @(f0,t) exp(-0.05*t) .* sin(2*pi*f0*t);

t = [0:500]/1000;
s = [];
for k1 = 1:length(fo)
    s = [s f(fo(k1),t)];
end
sound(s,1000)

[Image Analyst]

Or it could be "Mary had some MATLAB code"

[Star Strider]

Didn’t think of that, but definitely yes!

My personal fave is:

‘Twinkle, twinkle little star,
 Power equals I-squared R!’

[Davye Mak]

Oh, yeah, I found it true!! the tune is Mary had a little lamp. Thanks for your helps guys!! I really appreciate your help!!! Have goods day!!!

Davye

[John D'Errico]

Um, Mary had no lamp. Instead, she did have a wee little lamb.

[Matt Tearle]

Not bad, but how about adding a bit of timbre...?

fo=[494;440;392;440;494;494;494];
overtones = [1;0.6;0.5;0.4];  % play with these
f = @(f0,t) exp(-0.05*t) .* sum(bsxfun(@times,overtones,sin(2*pi*f0*bsxfun(@times,(1:length(overtones))',t))));
t = (0:5000)/10000;
s = [];
for k1 = 1:length(fo)
    s = [s f(fo(k1),t)];
end
sound(s,10000)

(And the award for Most Pointless MATLAB Code I've Written Today goes to...)