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Angle between two vectors in a for loop

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I need to find angles between vectors starting from 5th. These are the two loops i wrote:
A = [X;Y];
A = [A; zeros(1,50)];
W_wek = [1 0 0];
%W_wek = [0 1 0];
for k=1:length(A)
W_wek = [A(1,:)-B(1,:); A(2,:)-B(2,:); A(3,:)-B(3,:)];
end
In the first one I'm supposed to get the coordinates of the vectors, the variable looks like this:
In the second for loop i used the atan2d function combined with norm,cross:
Ang=[];
for l=5:length(W_wek)
Ang(l) = atan2d(norm(cross(W_wek(l-1,:),W_wek(l,:))),dot(W_wek(l-1,:),W_wek(l,:)));
end
I was sure it should work but it keeps giving me this error: Index in position 1 exceeds array bounds. Index must not exceed 3.
Any ideas how to fix this?
  1 Comment
dpb
dpb on 6 Jan 2022
for l=5:length(W_wek)
Ang(l) = atan2d(norm(cross(W_wek(l-1,:),W_wek(l,:))),dot(W_wek(l-1,:),W_wek(l,:)));
length() is a dangerous function -- it's defined as max(size(x)) so for your case above it will return 50.
You then use it as the upper limit on the l looping index and use l as the row index for the subscripting expression into the array. You've got the indices/limits turned around.
I recommend to not use length here at all and in most cases you'll want a specific size value just like here...

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Answers (1)

William Rose
William Rose on 8 Feb 2022
(I deleted my comment because I posted it before it was complete, and because I intended to post an answer rather than a comment. I'm not very good at the mechanics of posting.)
W_wek=2*rand(3,50)-1; %points uniform in the (-1...+1) cube
N=length(W_wek);
angle=zeros(1,N-5); %allocate array for angles
for i=5:N
angle(i)=acosd(dot(W_wek(:,i),W_wek(:,i-1))/(norm(W_wek(:,i))*norm(W_wek(:,i-1))));
end
fprintf('Angle: min=%.2f, max=%.2f, mean=%.2f\n',min(angle),max(angle),mean(angle));
Angle: min=0.00, max=170.65, mean=78.95
Angle is between 0 and 180.

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