damage equation for uniaxial compression

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suman Dahal
suman Dahal on 23 Dec 2014
Answered: Roger Stafford on 23 Dec 2014
(4αβ^2 E^(0^2 ) ε_1^2)/〖((β+ γ ) E^0-(1+α)k)〗^2 + ε_1^2-(ε_u^2 k)/(w(E^0-k)) =0
given values for above equation β= 0.2777 γ= 1.111 α=1.13885 E^0=30768.7 MPa START FROM 0.00000 TO 2.00000 WITH INCREAMENT O.00005 ALWAYS ε_u=0.0003 W=0.0049 K=????? AT DIFFERENT VALUES OF ε_1
I need to solve the above equation. Thank you for ur support

Answers (1)

Roger Stafford
Roger Stafford on 23 Dec 2014
By multiplying by the product of the two denominators, the equation becomes that of a cubic polynomial in k which will in general possess three roots. Which one do you want? You can use 'root's to find all three.
The variable you designate by "E^0" would necessarily have a value of 1 in matlab, since it represents the zero-th power of E. You need to use some other designation. The notation "E^(0^2 )" is even more dubious.

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