how to show my extracted features

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inter steller
inter steller on 11 Feb 2015
Commented: Image Analyst on 4 Jun 2017
i have a image eg: 400*300 size, but after i do feature extraction, it give me a vector for example like [11800 11811 11823......] . And now i need to show my extracted vector which is [11800 11811 11823......] ,anyoone can tell me how?? i have tried using reshape but it does not work since my extracted vector not same size with my original image ... it is a single 19128x1 vector only...

Answers (2)

Stalin Samuel
Stalin Samuel on 11 Feb 2015
%if 'feature' is the vector contains feature values then use
disp(feature)
  2 Comments
inter steller
inter steller on 12 Feb 2015
i tried and it just give me a column of coordinate vector, i nid to display it as a image , anny idea?
Image Analyst
Image Analyst on 12 Feb 2015
It's strange that you ignored my answer when you asked the same thing of me in my Answer. Any reason why? If you didn't ignore it and it didn't work for you, then post your non-working code.

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Image Analyst
Image Analyst on 11 Feb 2015
You can just put it by itself on the command line:
featureVector % No semicolon
to display it in the command window, or you could use fprintf if you want some more control over how it's formatted:
fprintf('%.2f ', featureVector);
or you could put it into a message and display it.
message = sprintf('%.2f ', featureVector);
uiwait(helpdlg(message));
or you could put it into a static text label in a GUI.
set(handles.text1, 'String', message);
or you could look at it in the variable editor. I could go on, but so as to not waste my time, how and where would you like to see it?
  11 Comments
Yealemzewud  Mekonnen
Yealemzewud Mekonnen on 4 Jun 2017
@Image Analyst I used HOG descriptor code which is posted by Sanyam Garg (<http://www.mathworks.com/matlabcentral/fileexchange/46408-histogram-of-oriented-gradients--hog--code-using-matlab>)
function [feature] = hog_feature_vector(im)
can you help me to change the feature to an image after the function returns the feature?
Image Analyst
Image Analyst on 4 Jun 2017
No - I suggest you ask Sanyam Garg about his code.

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