Continuous running of code
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I have been trying to implement a way to allow my code to run continuously on a MATLAB graph but with no avail. I have used the drawnow function which has helped me run it in real-time but I would like for the code to run like oscilloscope. Is there a function that I am missing?
3 Comments
Geoff Hayes
on 24 Mar 2015
Alex - yes, it is possible to do this. You should be able to modify the below code to suit your needs.
Answers (2)
Geoff Hayes
on 21 Mar 2015
Alex - you could try the following which will generate a sine wave and change the last second of data on each iteration of the while loop
figure;
hold on;
set(gca,'Color','k');
set(gca,'YLim',[-2 2]);
% generate five seconds of data with frequency f
fs = 200;
dt = 1/fs;
t = linspace(0,5-dt,5*fs);
f = 2;
a = 1;
y = a*sin(2*pi*t*f);
h = plot(t,y,'Color','g');
while true
% generate a new second of data
tn = linspace(max(t)+dt,max(t)+1,fs);
% randomly change the frequency
if rand>0.6
fn = randi(5,1,1);
else
fn = f;
end
yn = sin(2*pi*tn*fn);
% remove the old data and replace with the new
t = [t(fs+1:end) tn];
y = [y(fs+1:end) yn];
% update the plot
set(h,'XData',t,'YData',y);
pause(1);
end
Note how set is used to update the x and y data of the handle h which corresponds to plot graphics handle. Try the above and see what happens!
0 Comments
Shubham Hokarne
on 4 Jun 2018
Is there any command in matlab to run the program for infinite time and update the data ?
2 Comments
Walter Roberson
on 4 Jun 2018
Edited: Walter Roberson
on 4 Jun 2018
No, MATLAB does not have any transfinite operations, but you might be able to find some useful information about implementation of transfinite quantities in MATLAB from https://www.maths.ox.ac.uk/system/files/attachments/PartB2015-16_web_0.pdf
I think you will find it easier to execute indefinitely, updating as you go, instead of waiting until after an infinite time has passed.
Geoff Hayes
on 4 Jun 2018
Shubham - which program and which data (should be updated)? Please provide some context. And in the future, please don't post a question as an answer to a different question.
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