Function matchpairs does not work in MATLAB R2023a when I use a sparse cost matrix. Please help me out ASAP!
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Ulyana Grechaniuk
on 9 Apr 2024 at 3:28
Edited: Bruno Luong
on 11 Apr 2024 at 15:56
You can run this simple code and see my problem. Am I doing something wrong?
% testing matchpairs ----------------------------------------------------------------
clear;clc
% --- using matrix in usual form (not sparse) --- WORKS
M = 99*ones(16,16);
M(1,1) = 2;
M(2,1) = 1;
M(1,2) = 1;
M(3,2) = 2;
M(2,3) = 2;
M(4,3) = 1;
M(6,3) = 4;
M(3,4) = 1;
M(4,4) = 2;
M(7,4) = 4;
M(6,5) = 2;
M(8,5) = 1;
M(3,6) = 4;
M(5,6) = 2;
M(7,6) = 1;
M(4,7) = 4;
M(6,7) = 1;
M(10,7) = 2;
M(5,8) = 1;
M(9,8) = 2;
M(8,9) = 2;
M(12,9) = 1;
M(7,10) = 2;
M(11,10) = 1;
M(13,10) = 4;
M(10,11) = 1;
M(12,11) = 2;
M(14,11) = 4;
M(9,12) = 1;
M(11,12) = 2;
M(10,13) = 4;
M(13,13) = 2;
M(14,13) = 1;
M(11,14) = 4;
M(13,14) = 1;
M(15,14) = 2;
M(14,15) = 2;
M(16,15) = 1;
M(15,16) = 1;
M(16,16) = 2;
[matchings, unassignedRows, unassignedCols] = matchpairs(M,12345)
OUTPUT IS CORRECT:
% --- using sparse matrix --- DOES NOT WORK
Ms = sparse(16,16);
Ms(1,1) = 2;
Ms(2,1) = 1;
Ms(1,2) = 1;
Ms(3,2) = 2;
Ms(2,3) = 2;
Ms(4,3) = 1;
Ms(6,3) = 4;
Ms(3,4) = 1;
Ms(4,4) = 2;
Ms(7,4) = 4;
Ms(6,5) = 2;
Ms(8,5) = 1;
Ms(3,6) = 4;
Ms(5,6) = 2;
Ms(7,6) = 1;
Ms(4,7) = 4;
Ms(6,7) = 1;
Ms(10,7) = 2;
Ms(5,8) = 1;
Ms(9,8) = 2;
Ms(8,9) = 2;
Ms(12,9) = 1;
Ms(7,10) = 2;
Ms(11,10) = 1;
Ms(13,10) = 4;
Ms(10,11) = 1;
Ms(12,11) = 2;
Ms(14,11) = 4;
Ms(9,12) = 1;
Ms(11,12) = 2;
Ms(10,13) = 4;
Ms(13,13) = 2;
Ms(14,13) = 1;
Ms(11,14) = 4;
Ms(13,14) = 1;
Ms(15,14) = 2;
Ms(14,15) = 2;
Ms(16,15) = 1;
Ms(15,16) = 1;
Ms(16,16) = 2;
[matchings, unassignedRows, unassignedCols] = matchpairs(Ms,-1)
0 Comments
Accepted Answer
Ulyana Grechaniuk
on 10 Apr 2024 at 20:57
1 Comment
Bruno Luong
on 11 Apr 2024 at 15:54
Edited: Bruno Luong
on 11 Apr 2024 at 15:56
@Ulyana Grechaniuk you are welcome.
You should move your reply to comment using the cross arrows "Move" on the top right. Thanks.
More Answers (1)
Bruno Luong
on 9 Apr 2024 at 7:04
Edited: Bruno Luong
on 9 Apr 2024 at 8:46
Your sparse matrix filled default cost wit 0 not 99. Then your expectation on that the result is identocal for different cost matrices (regardless data structure using) is simply plain wrong.
If you fill sparse or dense matrix with the same values it give identical outputs:
% testing matchpairs ----------------------------------------------------------------
clear;clc
% --- using matrix in usual form (not sparse) --- WORKS
M = 99*ones(16,16);
M(1,1) = 2;
M(2,1) = 1;
M(1,2) = 1;
M(3,2) = 2;
M(2,3) = 2;
M(4,3) = 1;
M(6,3) = 4;
M(3,4) = 1;
M(4,4) = 2;
M(7,4) = 4;
M(6,5) = 2;
M(8,5) = 1;
M(3,6) = 4;
M(5,6) = 2;
M(7,6) = 1;
M(4,7) = 4;
M(6,7) = 1;
M(10,7) = 2;
M(5,8) = 1;
M(9,8) = 2;
M(8,9) = 2;
M(12,9) = 1;
M(7,10) = 2;
M(11,10) = 1;
M(13,10) = 4;
M(10,11) = 1;
M(12,11) = 2;
M(14,11) = 4;
M(9,12) = 1;
M(11,12) = 2;
M(10,13) = 4;
M(13,13) = 2;
M(14,13) = 1;
M(11,14) = 4;
M(13,14) = 1;
M(15,14) = 2;
M(14,15) = 2;
M(16,15) = 1;
M(15,16) = 1;
M(16,16) = 2;
[matchings, unassignedRows, unassignedCols] = matchpairs(M,12345)
matchings
Ms = sparse(M);
[matchings, unassignedRows, unassignedCols] = matchpairs(M,12345);
matchings
Cross check, now both filled with 0s
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
% --- using sparse matrix --- DOES NOT WORK
Ms = sparse(16,16);
Ms(1,1) = 2;
Ms(2,1) = 1;
Ms(1,2) = 1;
Ms(3,2) = 2;
Ms(2,3) = 2;
Ms(4,3) = 1;
Ms(6,3) = 4;
Ms(3,4) = 1;
Ms(4,4) = 2;
Ms(7,4) = 4;
Ms(6,5) = 2;
Ms(8,5) = 1;
Ms(3,6) = 4;
Ms(5,6) = 2;
Ms(7,6) = 1;
Ms(4,7) = 4;
Ms(6,7) = 1;
Ms(10,7) = 2;
Ms(5,8) = 1;
Ms(9,8) = 2;
Ms(8,9) = 2;
Ms(12,9) = 1;
Ms(7,10) = 2;
Ms(11,10) = 1;
Ms(13,10) = 4;
Ms(10,11) = 1;
Ms(12,11) = 2;
Ms(14,11) = 4;
Ms(9,12) = 1;
Ms(11,12) = 2;
Ms(10,13) = 4;
Ms(13,13) = 2;
Ms(14,13) = 1;
Ms(11,14) = 4;
Ms(13,14) = 1;
Ms(15,14) = 2;
Ms(14,15) = 2;
Ms(16,15) = 1;
Ms(15,16) = 1;
Ms(16,16) = 2;
[matchings, unassignedRows, unassignedCols] = matchpairs(Ms,-1);
matchings
Mf = full(Ms);
[matchings, unassignedRows, unassignedCols] = matchpairs(Mf,-1);
matchings
1 Comment
Bruno Luong
on 9 Apr 2024 at 7:17
One way to use sparse and keep filling 0 is to shift the value of the cost matrix
% testing matchpairs ----------------------------------------------------------------
Ms = sparse(16,16);
Ms(1,1) = 2;
Ms(2,1) = 1;
Ms(1,2) = 1;
Ms(3,2) = 2;
Ms(2,3) = 2;
Ms(4,3) = 1;
Ms(6,3) = 4;
Ms(3,4) = 1;
Ms(4,4) = 2;
Ms(7,4) = 4;
Ms(6,5) = 2;
Ms(8,5) = 1;
Ms(3,6) = 4;
Ms(5,6) = 2;
Ms(7,6) = 1;
Ms(4,7) = 4;
Ms(6,7) = 1;
Ms(10,7) = 2;
Ms(5,8) = 1;
Ms(9,8) = 2;
Ms(8,9) = 2;
Ms(12,9) = 1;
Ms(7,10) = 2;
Ms(11,10) = 1;
Ms(13,10) = 4;
Ms(10,11) = 1;
Ms(12,11) = 2;
Ms(14,11) = 4;
Ms(9,12) = 1;
Ms(11,12) = 2;
Ms(10,13) = 4;
Ms(13,13) = 2;
Ms(14,13) = 1;
Ms(11,14) = 4;
Ms(13,14) = 1;
Ms(15,14) = 2;
Ms(14,15) = 2;
Ms(16,15) = 1;
Ms(15,16) = 1;
Ms(16,16) = 2;
% Shift matrix
[I,J,K] = find(Ms);
fillvalue = 99;
Msshift = sparse(I,J,K-fillvalue,16,16);
[matchings, unassignedRows, unassignedCols] = matchpairs(Msshift,12345);
matchings
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