How do I put in a range of negative numbers?

25 views (last 30 days)
I've got this script: -
m=2
g=9.81
k=0.5
c=sqrt((m*g)/k)
v=[-6.264183904]
t=(-1*(c/2)*log((c+v)/(c-v)))/g
plot(v,t)
and I want my values for v to be equal to a range of values going from -c to 0. I can't seem to make it do it for some reason.

Accepted Answer

Image Analyst
Image Analyst on 25 Nov 2011
Try linspace, like this:
m=2
g=9.81
k=0.5
c=sqrt((m*g)/k)
v=linspace(-c, 0, 100);
t=(-1*(c/2)*log((c+v)./(c-v)))/g;
plot(v,t, 'bo-');
grid on;
% Enlarge figure to full screen.
set(gcf, 'units','normalized','outerposition',[0 0 1 1])
Note that because v is now an array some of the slashes needed to be changed to dot slashes.
  2 Comments
Tom
Tom on 25 Nov 2011
That's great thanks. I get the linspace command now I think. What's 'bo-'? And would you mind just explaining the bottom line a bit? Thanks again.
Walter Roberson
Walter Roberson on 25 Nov 2011
'bo-' is Blue lines with circular ("o-shaped") markers, using solid lines to connect the points.
Outerposition is difficult to explain. You can read the documentation about it, http://www.mathworks.com/help/techdoc/ref/axes_props.html#OuterPosition but I find it difficult to manipulate Innerposition and Outerposition to get predictable results.

Sign in to comment.

More Answers (1)

Disha Patel
Disha Patel on 12 Dec 2018
I have got this script :
close all;
clear all;
clc
n = -10:1:-1;
u(n)= 1;
p=(0.25).^(n).*u(n);
plot(n,p);
I want to scatter function "p" in negative side of the x axis so what should I do if I run this code the error seems like there should be positive and logical value of the variable "n" could anyone help me out of this?

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!