How datetime and integer or float value can co-habitate in an array?

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I am trying to save both a float or integer value together with a datetime value in an array. Anyway of making both these values cohabitate in an array?
d= 5.5
e = 05-Feb-2015 18:15:59
f= [d e]
Of course this is an error. But I am trying to map integers values to a datetime value. How i can do this. Should i change the datetime to a string?
  2 Comments
Jan
Jan on 26 Jun 2015
The datetime "e" is a string already. So you have actually:
e = '05-Feb-2015 18:15:59'
with the quotes.
Walter Roberson
Walter Roberson on 26 Jun 2015
Keep in mind that datetime is a newer object class, and members of that class print out without quotes.

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Accepted Answer

Steven Lord
Steven Lord on 26 Jun 2015
Use a cell array, as Azzi said, or use a table object.
x = 12345;
t = datetime('today');
A = table(x, t)
For a slightly larger table with some random data for today and the next 9 days:
x = randi(100, 10, 1);
t = datetime('today')+days((0:9).');
t.Format = 'dd-MMM-yyyy'; % Adjust the formatting of the dates to display only day, month, and year
A = table(x, t)

More Answers (1)

Azzi Abdelmalek
Azzi Abdelmalek on 26 Jun 2015
Edited: Azzi Abdelmalek on 26 Jun 2015
Use cell array
d= 5.5
e = '05-Feb-2015 18:15:59'
f= {d e}
or
d= 5.5
e =datenum( '05-Feb-2015 18:15:59')
f=[d e]
or use struct array
d= 5.5
e ='05-Feb-2015 18:15:59'
f.date=d
f.value=e
  9 Comments
Jan
Jan on 26 Jun 2015
I do not understand this sentence:
My second query is that my inital datetime array is very long
(about 3000 in length)..how do i convert it automatically between commas?
yashvin
yashvin on 29 Jun 2015
Sorry for the confusion. What i meant is that i have a very long stream of datetime array. I wanted to display it in a column or table fashion whereby each datetime value corresponds to an integer!

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