I want to transfer data from a for loop into a vector, i need to use rows of a matrix, every 3rd number(not every 3rd entry) in first column( 2 to 5 repeated numbers for each, tho random). Prob is output length unknown so difficult to prelocate

for x=[1,4,7,10,13,16,19,22,25,28,31,34,37,40,43,46,49,52,55,58,61,64,67,70,73,76,79,82,85,88,91,94,97,100,103,106,109,112,115,118,121,124,127,130,133,136,139,142,145,148,151,154,157,160,163,166,169,172,175,178,181,184,187,190,193,196,199,202,205,208,211,214,217,220,223,226,229,232,235,238,241,244,247,250,253,256,259,262,265,268,271,274,277,280,283,286,289,292,295,298,301,304,307,310,313,316,319,322,325,328,331,334,337,340,343,346,349,352,355,358,361,364,367,370,373,376,379,382,385,388,391,394,397,400,403,406,409,412,415,418,421,424,427,430,433,436,439,442,445,448,451,454,457,460,463,466,469,472,475,478,481,484,487,490,493,496,499,502,505,508,511,514,517,520,523,526,529,532,535,538,541,544,547,550,553,556,559,562,565,568,571,574,577,580,583,586,589,592,595,598,601,604,607,610,613,616,619,622,625,628,631,634,637,640,643,646,649,652,655,658,661,664,667,670,673,676,679,682,685,688,691,694,697,700,703,706,709,712,715,718,721,724,727,730,733,736,739,742,745,748]; %72 hour decimation=3, weekly 7, monthly 30

   A = (fromehfs(:,1)==x );
    out = fromehfs(A,:)

end

Answer 1

[Stephen23]

We can avoid the loop altogether by using the very efficient bsxfun instead:

x = [1,4,7,10,13,16,19,22,25,28,31,34,37,40,43,46,49,52,55,58,61,64,67,70,73,76,79,82,85,88,91,94,97,100,103,106,109,112,115,118,121,124,127,130,133,136,139,142,145,148,151,154,157,160,163,166,169,172,175,178,181,184,187,190,193,196,199,202,205,208,211,214,217,220,223,226,229,232,235,238,241,244,247,250,253,256,259,262,265,268,271,274,277,280,283,286,289,292,295,298,301,304,307,310,313,316,319,322,325,328,331,334,337,340,343,346,349,352,355,358,361,364,367,370,373,376,379,382,385,388,391,394,397,400,403,406,409,412,415,418,421,424,427,430,433,436,439,442,445,448,451,454,457,460,463,466,469,472,475,478,481,484,487,490,493,496,499,502,505,508,511,514,517,520,523,526,529,532,535,538,541,544,547,550,553,556,559,562,565,568,571,574,577,580,583,586,589,592,595,598,601,604,607,610,613,616,619,622,625,628,631,634,637,640,643,646,649,652,655,658,661,664,667,670,673,676,679,682,685,688,691,694,697,700,703,706,709,712,715,718,721,724,727,730,733,736,739,742,745,748];
B(:,2) = 1:6;
B(:,1) = [40,0,106,0,0,487]
idx = any(bsxfun(@eq,B(:,1),x),2);
out = B(idx,:)

which displays this in the command window:

>> Untitled
B =
    40     1
     0     2
   106     3
     0     4
     0     5
   487     6
out =
    40     1
   106     3
   487     6

This is a kind of code vectorization, which is important to learn if you want to use MATLAB efficiently.

[Jos (10584)]

I do not understand the question, but you can use ismember, rather then any and bsxfun to get idx:

idx = ismember(B(:,1),x)

[ian benford]

As you said very efficient, many thanks