How to get vectors y such that y* A = 0?

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I know that normally, you would do something like [W,D] = eig(A.') and then the rows of W.' are the left eigenvectors "y" of A such that yA = 0.
However, this is not what I want. I'm trying to find column vectors y with the following property: y* A = 0, where * is the conjugate transpose . How would I do this using eig?

Accepted Answer

John D'Errico
John D'Errico on 16 Jul 2015
Edited: John D'Errico on 16 Jul 2015
Nope. You would NOT use eig, since eig solves a different problem. Why use the wrong tool to solve a simple problem?
You need to find the vectors that lie in the null-space of the columns of A. For example...
A = randn(5,3) + i*randn(5,3);
N = null(A');
N'*A
ans =
-5.5511e-17 - 3.9552e-16i -9.7145e-17 + 8.3267e-17i -2.7756e-17 - 4.8572e-17i
2.3592e-16 - 2.2204e-16i 6.9389e-18 - 1.1102e-16i 3.5388e-16 - 4.4409e-16i
N is a column matrix, here with two columns. See that the transpose of those columns, when left multiplied times A, yields zero. Don't forget that ' is indeed a conjugate transpose, as you desired.

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