How can I count how many multi-dimension arrays in a matrix?
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For example, I have a 10 by 2 matrix 'B' as below.
B=[1 9; 2 9; 4 8; 1 0; 1 0; 1 1; 1 3; 1 3; 1 2; 1 2]
I want to find out how many rows are 1 2 The answer should be 2. I am using for loop as shown below.
z=0;
for f1=1:10
if B(f1,1)==1 && B(f1,2)==2
z = z+1;
end
end
This method works fine but when matrix 'B' gets bigger, it takes too much time. Is there any other ways to do this job?
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Accepted Answer
Andrei Bobrov
on 28 Jul 2015
Edited: Andrei Bobrov
on 28 Jul 2015
z = nnz(ismember(B,[1 2],'rows'));
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