Why is the if statement not working?
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this is my code - it is supposed to be a binary array, where the length of time (through the array) that the "1"s are held is determined by "time" - why is the if statement not working based off of the output of "time"?
function cube=cube(exp)
exp=zeros(60,96,10);
time=randi([3 7]);
if time==3
for j=1:size(exp,1);
for jj=1:size(exp,2);
rand=randi([1 8]);
exp(j,jj,rand:rand+2)=1;
end
end
elseif time == 4
for j=1:size(exp,1);
for jj=1:size(exp,2);
rand=randi([1 7]);
exp(j,jj,rand:rand+3)=1;
end
end
elseif time == 5
for j=1:s ize(exp,1);
for jj=1:size(exp,2);
rand=randi([1 6]);
exp(j,jj,rand:rand+4)=1;
end
end
elseif time == 6
for j=1:size(exp,1);
for jj=1:size(exp,2);
rand=randi([1 5]);
exp(j,jj,rand:rand+5)=1;
end
end
elseif time == 7
for j=1:size(exp,1);
for jj=1:size(exp,2);
rand=randi([1 4]);
exp(j,jj,rand:rand+6)=1;
end
end
cube=exp
end
1 Comment
the cyclist
on 3 Aug 2015
One suggestion, aside from trying to solve your main problem, is that you should not be using MATLAB keywords as variable names, because the code may behave in unexpected ways, and also the code simply becomes very confusing (especially for veteran users). In your case, exp and rand should be avoided as variable names.
Accepted Answer
the cyclist
on 3 Aug 2015
One problem is that in the elseif statement where you check if time == 5, you have
for j=1:s ize(exp,1);
instead of
for j=1:size(exp,1);
0 Comments
More Answers (1)
the cyclist
on 3 Aug 2015
Edited: the cyclist
on 3 Aug 2015
You need
time==3
instead of
time=3
== is the "determine equality" operator. = is the assignment statement.
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