Interpolation points: The grid vectors do not define a grid of points that match the given values.

Hello, I'm having a problem to interpolate some points. I think that is a easy thing and I don't see whats is the problem. I want with data_x, data_y and range use iterp1, when: data_x = 0:0.001:1 or data scale data_y = vector 1000x1 with diferent values range = 0:0.004:1

and I do,

data_interp = interp1(data_x, data_y, range);

I solve the problem with the repeated values of data_y, but now, I have this error:

The grid vectors do not define a grid of points that match the given values.

thanks.

[Eric Sirott]

data_x in this example will be a 1001x1 vector which isn't the same size as 1000x1

Answer 1

[John D'Errico]

Um, you tell us that x is a vector of length 1001. (How many points are in the vector 0:.001:1 ?) Then you tell us that y is a vector of length 1000.

Do you see the disconnect? Go back and read the error message again. In general, interpolation requires a set of (x,y) pairs, such that we have y as a function of x at EACH AND EVERY value for x. You do not satisfy that requirement.

[ViniAlmeida]

Thanks for the fast replie, the problem was this. Do you know whats mean I have a data and find a data scale? For example, I'm using a function in matlab that make a data fit with a binomial distribution, the parameters are this, data and data scale. My data are values between 0 and 1, there are 668700 points that I have, so, whats data scale?