Attempted to access t(3); index out of bounds because numel(t)=2. Error in Project_1c (line 17) t(n+1)=t(n​)-f(n).*((​t(n+1)-t(n​))/(f(n+1)​-f(n)));

clc;
clear all;
close all;

f=@(t)(sin((pi)*t).*exp(-t));
t1=linspace(-1,5,100);
f1=f(t1);
plot(t1,f1)

n= 1; %index start
tol= 100; %convergence tolerance
t(1)= -1; %intial guess
t(2)= 0; %intial guess
Tol=1e-6;
while tol>Tol
    n=n+1 
    t(n+1)=t(n)-f(n).*((t(n+1)-t(n))/(f(n+1)-f(n)));
    f(n+1)=f(t(n+1))
    tol=abs(t(n+1)-t(n))
end

Answer 1

[Walter Roberson]

t(n+1)=t(n)-f(n).*((t(n+1)-t(n))/(f(n+1)-f(n))) defines t(n+1) in terms of t(n+1) which does not exist yet.

If the expression is intended to be a recurrence formula, then you will find that it is satisfied for t(n) being constant, for all non-zero (f(n)-f(n+1)) .