How do I calculate a derivative of a time-variable parameter in SimBiology ?

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In SimBiology project I have a parameter that is time dependent. I need its time derivative to use in a formula. How do I calculate the time derivative in Simbiology ?
  3 Comments
Sergey Ermakov
Sergey Ermakov on 9 Sep 2015
Hi Ingrid, actually I am looking for a general case since I anticipate more than one case where I'll need time derivative dY/dt. I don't mind delta Y/delta t, but this means I need Y value from previous time step as well (how to get that ?). I also need to know time step (is there a function to call or something like that?). And this is for simple 1-st order approximation. If you know how to do this please let me know. Thank you.

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Accepted Answer

Arthur Goldsipe
Arthur Goldsipe on 21 Oct 2015
Hi Sergey,
There is no way to directly access the time derivative or previous value of state in SimBiology. There are different workaround depending on what exactly you need to do. I just mentioned one approach in a comment on the previous "answer". The basic idea there turns the problem around: If you can write an expression for the time derivative of your parameter, you can store the value of the derivative by using that expression in a repeated assignment rule, and then you can use this parameter to define a rate rule.
If you do not have an analytic expression for the time derivative of your parameter, there is no straightforward way to access the derivative during simulations.
-Arthur
  1 Comment
Sergey Ermakov
Sergey Ermakov on 21 Oct 2015
Hello Arthur,
unfortunately more often you don't have an analytical expression for the derivative. You have a variable that depends on many things in the model and you need to calculate a derivative, that will be used in a number of other expressions. I think the ability to calculate the derivative that would a valuable function to have in SimBiology. Thank you.

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More Answers (1)

Chao'en Li
Chao'en Li on 20 Oct 2015
I met the same problem.
For a reaction a + b = c, I set unknown Kinetic Law, with Reaction Rate as k*Ca*Cb,(Ca and Cb are concentrations of a and b)and repeated assignments: dc_dt = k*Ca*Cb, and Ca = Ca_0 + time*dc_dt (dc_dt is the derivative dc/dt, Ca_0 is the initial concentration of a).
But I got error message as "Repeated assignment rules cannot create algebraic loops (for example, 'x = y' and 'y = x'). The following rules introduce algebraic loops into the model: Ca = Ca + time*dc_dt'"
How to write the following rules: dc/dt(i)=k*Ca(i)*Cb(i), Ca(i+1)=Ca(i)+dc/dt(i)*dt(i)?
  1 Comment
Arthur Goldsipe
Arthur Goldsipe on 21 Oct 2015
Repeated assignments are not systems of equations that are solved simultaneously. They are simple assignments that are evaluated sequentially at each time step, so they must have a well-defined order of evaluation. You cannot simultaneously have a repeated assignment rule for dc_dt that depends on Ca and a repeated assignment rule for Ca that depends on dc_dt.
I think the real problem is that the rule for Ca isn't really doing what you want. You want Ca to be defined by integrating dc_dt. In SimBiology, you do that with a rate rule. So what I think you want to do is:
  1. Add a repeated assignment rule, "dc_dt = k*Ca*Cb", and
  2. Add a rate rule, "Ca = dc_dt"
One thing that is potentially confusing here is that the left-hand side of the rate rule really means "the time derivative of Ca". In other words, a more traditional mathematical representation of this rate rule would be "d(Ca)/dt = dc_dt".

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