Encoding Binary to DNA sequencing

6 views (last 30 days)
I am trying to convert the string into binary and sequencing with DNA,but i am getting error as follows :
Attempted to access bases(145); index out of bounds because numel(bases)=4.
Error in ==> filename at 21
result((k+1)/2) = bases(index);
What is the solution for this? Here is the code:
clc;
ui=input('enter the message:','s')
decString = unicode2native(ui,'utf-8')
hexString = dec2hex(decString)
binaryArray= dec2bin(decString,8)
bases = 'ATGC';
for k = 1 : 2 : length(binaryArray)
% Convert these two digits into a number 1 - 4.
index = 2 * binaryArray(k) + binaryArray(k+1) + 1;
% Use that index to assign a letter to our result.
result((k+1)/2) = bases(index);
end
% Display in command window:
result
Thank you
  2 Comments
Shiva Reddy
Shiva Reddy on 7 Feb 2021
It is giving error like index exceeds (4)
Walter Roberson
Walter Roberson on 7 Feb 2021
Yes, that is exactly the problem that was discussed in the Answer.

Sign in to comment.

Accepted Answer

Image Analyst
Image Analyst on 25 Sep 2015
bases has only 4 elements so index must stay in the range 1,2,3,4 not 145 like you have it. Think about the logic some more.
  5 Comments
Meghashree G
Meghashree G on 26 Sep 2015
Edited: Walter Roberson on 26 Sep 2015
The solution i got was
TGAC
TCAG
TCGT
TCAA
TCTA
TGCC
Its a vector right?
i want it to be something like this
TGAC
TCAG
TCGT
TCAA
TCTA
TGCC
i have to this sequence to other side.
Walter Roberson
Walter Roberson on 26 Sep 2015
I do not see the difference between what you got and what you want.
To answer your question, though: No, it is not a vector, it is an array. Character strings in MATLAB are arrays, not individual entities. The "result" variable above is char of size 6 x 4
If you want it as a cell array of strings, then use cellstr(result)

Sign in to comment.

More Answers (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!