BITXOR OPERATION
3 views (last 30 days)
Show older comments
Hello I want to do the "bitxor" operation as shown in below code. But since bitxor takes only 2 arguments the following code gives ERROR. Please suggest a solution. Mail me at lokesh_jolly05@yahoo.co.in
L(3*(i-1)+1)=mod(bitxor(B1(3*(i-1)+1),uint64(mod((abs(X(i))-floor(abs(X(i))))*10^14,256)),256));
3 Comments
Accepted Answer
Walter Roberson
on 26 Dec 2011
You have a bracket misplaced.
L(3*(i-1)+1)=mod(bitxor(B1(3*(i-1)+1),uint64(mod((abs(X(i))-floor(abs(X(i))))*10^14,256))),256);
Notice the ')' after 256 was moved to the end of the previous argument.
15 Comments
More Answers (0)
See Also
Categories
Find more on Matrix Indexing in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!