How can I repeat this random process 3 times so I can get 3 different versions of the variable "number"?
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function rollingdice2
i = 1;
modelaparents = 100;
modela= randi(6,1,modelaparents);
modelaparents = length(modela);
number1(1,i) = modelaparents;
while modelaparents > 0;
i = i + 1;
modela= randi(6,1,modelaparents);
modelaparents = length(modela(modela ~= 6));
number1(1,i) = modelaparents;
end
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Answers (1)
Jan
on 18 Oct 2015
Edited: Jan
on 18 Oct 2015
Your function with an output argument:
function number = rollingdice2
i = 1;
modelaparents = 100;
modela = randi(6,1,modelaparents);
modelaparents = length(modela);
number(1,i) = modelaparents;
while modelaparents > 0;
i = i + 1;
modela= randi(6,1,modelaparents);
modelaparents = length(modela(modela ~= 6));
number(1,i) = modelaparents;
end
calling from your main function:
numberList = cell(1, 3);
for k = 1:3
numberList{k} = rollingdice2;
end
Now you have 3 results as elements of a cell. You've acked for 3 different results. If this detail matters, you have to compare the results with each other and call the function until you have unique results.
2 Comments
Walter Roberson
on 19 Oct 2015
You have an "end" at the bottom that can only match the "function" line. That would, however, imply that your lines starting from "numerList" are part of justrolling.m . If that is the case then each time you invoked justrolling it would get down to the bottom and invoke justrolling again recusively, infinitely.
The code you have starting from "numerList" cannot be in the same function justrolling .
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