Asked by Richard
on 8 Jan 2012

How might I define a function handle?

For example, I want to define a function f(x)=2*x^3+7*x^2+x

I want MATLAB to evaluate f(x) at random values x. I have heard of feval and fhandles, but I don't know how to do it.

Thanks.

Answer by Chandra Kurniawan
on 8 Jan 2012

Accepted answer

Hi, Richard.

First, you need to create a new m-file then type this code

function y = f(x) y = 2 * (x^3) + 7 * (x^2) + x;

Save with filename 'f.m'

Then create a new m-file and type this code

x = randi(7); y = f(x)

**randi** will generate random number

Chandra Kurniawan
on 8 Jan 2012

to evaluate this function just type :

y = feval(@f,x)

Richard
on 8 Jan 2012

Thanks, Chandra! :)

Salaheddin Hosseinzadeh
on 13 Mar 2014

The problem or lets say the dificulty of this code is that this couple of lines should be saved as a function and I personally don't wanna do that for a simple function like this! or even complicated ones!

Not my favorite way of defining a function

Answer by Walter Roberson
on 8 Jan 2012

Function handle version:

f = @(x) 2*x^3+7*x^2+x;

Then f is already the function handle, and you can call f(3.7) (for example)

There is no need to use feval() for this, but you could.

Salaheddin Hosseinzadeh
on 13 Mar 2014

I rather this anonymous way of defining a function! It's way easier. I also know another way of doing this, surprisingly nobudy mentioned that so far! lol I'm gonna put it in the answers.

Answer by Junaid
on 8 Jan 2012

Dear Richard,

To define a function in matlab you can do following syntax of given function:

function n = F(x)

n= 2*x^3+7*x^2+x;

that is it. You can put end at the end of function. But it is also acceptable not to put to various matlab versions. If you put end for one function then you have to put for all function in single m file.

then you can generate random numbers, either integer or double, and can get the values of this function.

Richard
on 8 Jan 2012

Thanks, Junaid! :)

Answer by cyril
on 21 Mar 2014

Edited by cyril
on 21 Mar 2014

> f = @(x) 2*x^3+7*x^2+x; > f(0) 0

surprising no one mentioned anonymous functions...

Salaheddin Hosseinzadeh
on 21 Mar 2014

@ Cyril

Walter did, just make sure you checked the other answers and comments!

Answer by samy youssef
on 11 Mar 2015

Edited by Walter Roberson
on 26 Sep 2016 at 20:50

here is a function i developed to calculate the log of any number with different base:

function d =log_for_diff_base(myNumber,myBase) x=log(myNumber); y=log(myBase); d=x/y; end

Walter Roberson
on 26 Sep 2016 at 20:50

Okay... but irrelevant to the original question.

Answer by Nikitha Challa
on 26 Sep 2016 at 19:15

x = x + a/x 2 in matlab code

John D'Errico
on 26 Sep 2016 at 20:54

Not a function at all. This is not even valid MATLAB code as written.

Walter Roberson
on 26 Sep 2016 at 20:54

That does not appear to be a question, and it is not an Answer to what was asked here?

If the question is to solve the equation

x == x + a/(x^2)

then for finite `a` values, the solutions are -inf and +inf as a/(x^2) would be 0 for those values, leading to the equality -inf == -inf and +inf == +inf

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