How to divide a matrix by each column of an array, need your help!

I would like to divide each column by an array. for instance,

clear

clc

A(1:5,1:5) = 5;

B= [1 2 3 4 5 ]

C=A/B

the answer I am looking for is

5/1 5/2 5/3 5/4 5/5

5/1 5/2 5/3 5/4 5/5

5/1 5/2 5/3 5/4 5/5

5/1 5/2 5/3 5/4 5/5

5/1 5/2 5/3 5/4 5/5

I need a much faster way than A(1)/B(1)

any help is much appreciated!

[savannah Roemer]

I have been trying

C=zeros(5,5)

for i=1:5

 for j=length(B)

    C=A(i)/B(j)
    C(i,j)=C

 end  
end

[Star Strider]

Avoid the loop!

Use bsxfun!

Answer 1

[Star Strider]

The bsxfun function is perfect for this:

A(1:5,1:5) = 5;
B= [1 2 3 4 5 ];

C = bsxfun(@rdivide, A, B)

format rat
C

Results:

C =

              5          2.5       1.6667         1.25            1
              5          2.5       1.6667         1.25            1
              5          2.5       1.6667         1.25            1
              5          2.5       1.6667         1.25            1
              5          2.5       1.6667         1.25            1

C =

         5              5/2            5/3            5/4            1       
         5              5/2            5/3            5/4            1       
         5              5/2            5/3            5/4            1       
         5              5/2            5/3            5/4            1       
         5              5/2            5/3            5/4            1