How to transform a cell array of cells in a matrix

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Problem: I have a cell array and every cell of this array has an other cell that contains a string: I want to trasform the cell array in a matrix of strings. How can i do? I have tried to use cell2mat but matlab gives an error:
'Cannot support cell arrays containing cell arrays or objects.'
I have A, in the attached .mat file, which is a vector of strings, and I want to divide prefix to postfix. To do it I use this code :
for k=1:25
[matches(:,k), postfix(:,k)] = regexp(A,sprintf('%d%d(.*)',digits{1}(k),digits{2}(k)),'match','once','tokens');
end
This code creates postfix (attached matlab.mat). I want that postfix is a matrix, and I don't know how transform it.
  1 Comment
Star Strider
Star Strider on 30 Nov 2015
Edited: Star Strider on 30 Nov 2015
The cell array in your ‘matlab.mat’ file seems to be 93% empty, and at least some of the non-empty cells contain only ''.

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Answers (2)

Image Analyst
Image Analyst on 30 Nov 2015
Extract it first, then use cell2mat:
for k = 1 : length(ca)
thisCellContents = ca{k}; % thisCellContents is another cell - the cell inside this cell.
matrix = cell2mat(thisCellContents);
end
Adapt as needed, for example if it's a 2D array of cells or whatever.
  3 Comments
Image Analyst
Image Analyst on 30 Nov 2015
What did thisCellContents produce? Was there anything in it? Star Strider says your mat file is empty everywhere.
ely may
ely may on 1 Dec 2015
Edited: ely may on 1 Dec 2015
the matlab.mat file is not empty everywhere: if you control, it isn't while thisCellContents is empty.
Star Strider:
The cell array in your ‘matlab.mat’ file seems to be 93% empty, and at least some of the non-empty cells contain only ''.

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Stephen23
Stephen23 on 30 Nov 2015
Edited: Stephen23 on 30 Nov 2015
>> X = {{'A'},{'bb'};{'CCC'},{'d'}}
X =
{1x1 cell} {1x1 cell}
{1x1 cell} {1x1 cell}
>> Y = reshape([X{:}],size(X))
Y =
'A' 'bb'
'CCC' 'd'
  6 Comments
ely may
ely may on 1 Dec 2015
Edited: ely may on 1 Dec 2015
I have no secret! Now I post my code (I think it wasn't necessary). I add it in the question. Sorry but I think that the question was clear.
Image Analyst
Image Analyst on 1 Dec 2015
Well it was necessary because we can now see that your code doesn't look like Stephen's code. Sorry, I have to leave for work now and I don't have time now to fix your code.

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